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3 years ago

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A sample of nitrogen gas has a volume of 578 mL and a pressure of 124.1 kPa. What volume would the gas occupy at 80.2 kPa if the

temperature remains constant?

1 answer:

Nataly_w [17]3 years ago

4 0

Answer:

V2 = 894.4mL

Explanation:

P1= 124.1, V1= 578mL, P2 = 80.2kPa, V2= ?

Applying Boyle's law

P1V1 = P2V2

Substitute and simplify

124.1*578=80.2*V2

V2= 894.4mL

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Calculate the Ka of your acetic acid solution. Discuss this calculation. Based on the value of Ka, is acetic acid a strong acid

lord [1]

Based on our knowledge of strong and weak acids, we can confirm that the Ka value for acetic acid will be relatively low since it is a weak acid.

Acids can be strong or weak. This is determined by its <u><em>tendency to break apart into ions or stay together to form molecules.</em></u> Although somewhat counter-intuitive, strong acids are those that are most likely to break apart and therefore contain a <em><u>high number of </u></em><em><u>ions </u></em><em><u>within their solutions</u></em>.

Weak acids, on the other hand, are those that<em><u> tend to stay together in the form of </u></em><em><u>molecules </u></em><em><u>and therefore possess very </u></em><em><u>low ion counts </u></em><em><u>in their solutions.</u></em> The acid dissociation constant, Kₐ, is used to measure whether an acid is weak or strong and how much so. In the case of Acetic acid, the ka measurement will offer a low value, indicating a weak acid.

To learn more visit:

brainly.com/question/4131966?referrer=searchResults

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2 years ago

The number of B2H6 molecules

zlopas [31]

Answer:

6.022 × 10²³ molecules of B₂H₆

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

B₂H₆ molecules:

21.63 g = one mole of B₂H₆= 6.022 × 10²³ molecules of B₂H₆

8 0

3 years ago

Which of the following decomposition reactions is/are correct?

qwelly [4]

<span>A) 2NaOH -> 2Na + O2 + H2
is not correct since Na is unstable

B) 2NaOH -> 2Na + H2O + 1/2O2
is not correct since Na is unstable

C) 2NaOH -> Na2O + H2O
is correct since N2O is stable

D) 2NaOH -> 2Na + H2O2
is not correct since Na is unstable</span>

7 0

3 years ago

Read 2 more answers

You place 40.6 ml of 0.659 M NaOH in a coffee- cup calorimeter at 25.00°C and add 71.3 ml of 0.659 M HCl, also at 25.00°C. After

faust18 [17]

Answer:

ΔH of reaction is 62,3 kJ/mol

Explanation:

For the reaction:

HCl + NaOH → H₂O + NaCl

The heat transfer in the reaction (q) =

q = Specific heat × mass × ΔT

The mass is 40,6 mL + 71,3 mL × (1g/mL) = 111,9 g

And ΔT is 28,57 - 25,00 = 3,57°C

q = 4,184 J/gK × 111,9 g × 3,57°C = <em>1671 J</em>

The moles of NaOH are:

0,0406 L×0,659 M = 0,0268 moles

And the moles of HCl are:

0,0713 L ×0,659 M = 0,0470 moles

The moles of reaction are the moles of NaOH because are the limiting reactant. 0,0268 moles

ΔH of reaction is q/moles of reaction. Thus:

ΔH of reaction = 1671J/0,0268 moles = 62350 J/mol ≡ 62,3 kJ/mol

I hope it helps!

8 0

3 years ago

The atoms of Group 7A elements _____ electrons when they form ions.

nikitadnepr [17]

The answer is B. gain. The elements from group 7a is F, Cl, Br, I... These elements has 7 electrons at the outer shell. And they are likely to gain one electron to stay at stable status.

8 0

2 years ago