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tangare [24]
3 years ago
7

A sample of nitrogen gas has a volume of 578 mL and a pressure of 124.1 kPa. What volume would the gas occupy at 80.2 kPa if the

temperature remains constant?
Chemistry
1 answer:
Nataly_w [17]3 years ago
4 0

Answer:

V2 = 894.4mL

Explanation:

P1= 124.1, V1= 578mL, P2 = 80.2kPa, V2= ?

Applying Boyle's law

P1V1 = P2V2

Substitute and simplify

124.1*578=80.2*V2

V2= 894.4mL

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Suppose that 273 of a substance displaces 26ml of water what is the substance
Llana [10]
273g/25 mL = 10.92 (that's the density)
What has a density of 10.92 grams/mL?  I don't know but I bet it's in your notes or on the worksheet.
3 0
3 years ago
A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.
MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

A.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

B.

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

C.

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0
2 years ago
HELP !!!!!!! ASAP !!!!!!!!!!!!!!
Dmitry [639]
The color changes, heat change, smell change, are a few
4 0
3 years ago
Read 2 more answers
The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell
tankabanditka [31]

Explanation:

In a voltaic cell, oxidation reaction occurs at anode whereas reduction reaction occurs at the cathode.

Hence, the half-cell reaction taking place at anode and cathode will be as follows.

At anode (Oxidation) : Cr(s) \rightarrow Cr^{3+}(aq) + 3e^{-} ...... (1)

At cathode (Reduction) : Ag^{+}(aq) + 1e^{-} \rightarrow Ag(s)

So, in order to balance the half cell reactions, we multiply reduction reaction by 3. Hence, reduction reaction equation will be as follows.

              3Ag^{+}(aq) + 3e^{-} \rightarrow 3Ag(s)  ........ (2)

Therefore, overall reaction will be sum of equations as (1) + (2). Thus, net reaction equation is as follows.

      Cr(s) 3Ag^{+}(aq) \rightarrow Cr^{3+}(aq) + 3Ag(s)          

         

6 0
3 years ago
Vitamin C has an empirical formula of C3H4O3 and a molecular mass of 176 amu. What is the molecular formula of vitamin C?
Vinvika [58]

Answer:

(C3H4O3) x 2 = C6H8O6, the molecular formula for Vitamin C.

3 0
3 years ago
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