Answer:
The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point
Explanation:
To solve the above question we have the given variable as follows
ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole
However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.
The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles
Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ
I don’t understand your language sorry
Use the following equation:
Given # of moles * molar mass (g) per mol = Mass (g)
This gives us 11.9 x <span> 51.9962 (g) per mol.
618.75 moles</span>
Answer:
Liquid
Explanation:
Liquid can change into all states of matter. For example, if you boil it, it becomes a gas, if you freeze it, it becomes a solid, and if you split the atoms, it can turn into a plasma. In conclusion, any state of matter has potential energy that needs a little push to activate it, hence the one of newtons laws of physics; every action has an equal and opposite reaction.
