Answer:
= 5.193 g
Explanation:
Half life is the time taken by a radioactive element to decay by half its original amount. Therefore, since half life of carbon-14 is 5700 years, then it would take 5700 years for a sample of carbon-14 to decay by half of its original amount.
Using the formula;
New mass = Original mass × (1/2)^n, where n is the number of half lives.
n = Period taken/Half life = 6350 years/5700 years =1.114
Therefore;
New mass = 11.24 × (1/2)^1.114
= 5.193 g
Hence, a mass of 5.193 g of Carbon-14 would remain after 6350 years.
The curves absorb the food and sort of squish it and make it easier to digest then the food goes into the stomach acid and kind of burns and become and little softer<span> or in other words by allowing the stomach to stretch in order to accommodate large meals and get grip and move food during the digestion process. </span>
I believe this process is called cellular respiration.
Answer:
1.28 ×10^-4m
Explanation:
Interference is the superimposition of the wavefront. The superimposition causes bright and dark fringes.
The dark fringe is formed when the additional distance traveled is equal to the multiple wavelength integrals.
From the question, the parameters given are; Wavelength of the light,λ= 600nm, Distance of the screen (D) = 1.44m, order of the bright fringe (m) = 4, Distance of the 4 order fringe (y) = 2.7 cm.
Therefore, for the maximum bright fringe;
dy/D=mλ-----------------------------------------------------------------------------------------------------------------------(1)
Therefore, slotting in equation (1);
d×0.027/1.44=4×600×10^-9
d= 1.28×10^-4 m.
Answer:
6.24 x 10-3 M
Explanation:
Hello,
In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:
![Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BBrO%5E-%5D%7D%7B%5BHBrO%5D%7D)
Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change 
, we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:
Thus, we obtain a quadratic equation whose solution is:
Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.
Best regards.
