Answer:
60%
Step-by-step explanation:
You can solve this problem by setting up a system of equations.
Let's say that the number of tickets bought by students in the first year is x, and the number bought by continuing students is y. From there, you can set it up like this:
0.4x+0.2y=160
x+y=500
Now, you can multiply the first equation by 5 on both sides to get:
2x+y=800
Subtracting the second equation from the first equation now yields:
x=300
y=200
Since 300 of the 500 tickets bought were from the first year students, and 300/500 is 0.6, 60% of the students who bought the ticket were first year students. Hope this helps!
Answer:
Amount borrowed from friend = 4000
From Bank = 8000
From insurance = 3200
Step-by-step explanation:
Given that:
Amount borrowed = $15200
Let amount borrowed from friend = x
x at 5% = 0.05x
From Bank = 2x at 8% = 0.08*2x = 0.16x
From insurance = 15200 - (x + 2x) at 4%
From insurance = 15200 - 3x at 4% ; (15200 - 3x)* 0.04 = 608 - 0.12x
Interest paid in first year = $968
Simple interest = principal * rate * time
968 =
968 = (0.05x + 0.16x + 608 - 0.12x)
968 - 608 = 0.05x + 0.16x - 0.12x
360 = 0.09x
x = 360 / 0.09
x = 4000
Hence,
Amount borrowed from friend = 4000
From Bank = 2x = 4000 * 2 = 8000
From insurance = 15200 - (4000 + 8000) = 3200
Answer:
a. 60 boys
b. 228 total students
Step-by-step explanation:
a. If there are 45 girls and the ratio of girls to boys is 3:4, then there are 60 boys. The common multiple is 15.
3 * 15 = 45
4 * 15 = 60
45:60 = 3:4
——————————
b. First we need to find out how many boys there are.
95 / 5 = 19
19 * 7 = 133
So, there are 133 boys and the given number of girls is 95. To find out how many total students there are, we need to add 133 and 95.
133 + 95 = 228
A) <span>Understanding the terms of a contract is important because a person must be certain of the obligations towards the other party, and must also be aware of penalties incurred if those obligations are not met.</span>
Answer:
The correct option is 1.
Step-by-step explanation:
The difference of cubes is defined as
![a^3-b^3=(a-b)(a^2+ab+b^2)](https://tex.z-dn.net/?f=a%5E3-b%5E3%3D%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29)
The given expression is
![x^6-27](https://tex.z-dn.net/?f=x%5E6-27)
It can be written as
![x^6-3^3](https://tex.z-dn.net/?f=x%5E6-3%5E3)
Using the property of exponent, the above expression can be written as
![[\because (x^m)^n=x^{mn}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28x%5Em%29%5En%3Dx%5E%7Bmn%7D%5D)
This is a difference of cubes.
Therefore the correct option is 1.