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2 years ago

11

what is the main difference between a substance going through a physical change and one going through a chemical ?

2 answers:

Nata [24]2 years ago

4 0

Answer: <em>Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. </em><u><em>Chemical changes are also known as chemical reactions.</em></u>

Ainat [17]2 years ago

3 0

Answer: Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.

Explanation:

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Identify each unit as belonging to SI units or US Customary units.

torisob [31]

Answer:

<em>SI Units</em>

Meter

Kilogram

Kelvin

<em>US Customary Units and English Units</em>

Gallon

Mile

Pound

Degrees Fahrenheit

Explanation:

The SI units or International System of Units are the widely used metrics of measuring a physical quantity. It has specific abbreviations.

The US customary units is a measurement system where it is widely used in the united states. This system of unit also has abbreviations.

There are also conversion scales that are used to convert a unit from one metric system to the other.

For example, the conversion of mile to SI unit is given by the formula

1 mile = 1609.4 meters

Similarly,

1 pound = 0.453592 Kg

6 0

3 years ago

The drawing shows two frictionless inclines that begin at ground level (h = 0 m) and slope upward at the same angle θ. One track

Elena L [17]

Answer:

a). $H=2.45m$

b). $H_{max}=1.94m$

Explanation:

For the block that stays on the track, its maximal height is attained when all of the kinetic energy is converted to potential energy

a).

The height for the block on the longer track can by find using this equation:

$\frac{1}{2}*m*v_o^2=m*g*H$

Cancel the mass as a factor in each element in the equation

$H=\frac{v_o^2}{2*g}$

$H=\frac{(6.94m/s)^2}{2*9.8m/s^2}$

$H=2.45m$

b).

The other lost some kinetic energy so, use a projectile motion to determine the total height for the other bock:

$E_k=E_p$

$E_k=m*g*H_1$

$E_k=\frac{1}{2}*m*v_o^2-\frac{1}{2}*m*v^2$

$m*g*H_1=\frac{1}{2}*m*(v_o^2-v^2)$

Solve to v'

$v^2=v_o^2-2*g*H_1$

$v=\sqrt{v_o^2-2*g*H_1}=\sqrt{(6.94m/s)^2-2*9.8m/s^2*1.25m}$

$v=4.8m/s$

$H_{max}=H_1+\frac{v^2*sin(50)}{2*g}=1.25m+\frac{(4.8m/s)^2*sin(50)}{2*9.8m/s^2}$

$H_{max}=1.94m$

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Why are force fields necessary to describe gravity?

artcher [175]

Gravity is a non-contact force.

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True or False: The average atomic mass is always closer to the isotope with the largest mass

svlad2 [7]

The awnser would be True. Hope I helped!

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3 years ago

A rocket is being launched straight up. Air resistance is not negligible.

Yanka [14]

Answer:

hope this will help you

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2 years ago

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