neutralization reactions occur when you combine two extremely reactive substances together for the purpose of rendering them inactive, or neutral.
Answer:
a) 113N
b) 0.37
Explanation:
a) Using the Newton's second law:
\sum Fx =ma
Since the crate doesn't move (static), acceleration will be zero. The equation will become:
\sum Fx = 0
\sumFx = Fm - Ff = 0.
Fm is the applied force
Ff is the frictional force
Since Fm - Ff = 0
Fm = Ff
This means that the applied force is equal to the force of friction if the crate is static.
Since applied force is 113N, hence the magnitude of the static friction force will also be 113N
b) Using the formula
Ff = nR
n is the coefficient of friction
R is the reaction = mg
R = 31.2 × 9.8
R = 305.76N
From the formula
n = Ff/R
n = 113/305.76
n = 0.37
Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37
Given :
Potential ,
![P=644 \times 10^6\ V\\ \\P=6.44\times 10^8\ V](https://tex.z-dn.net/?f=P%3D644%20%5Ctimes%2010%5E6%5C%20V%5C%5C%20%5C%5CP%3D6.44%5Ctimes%2010%5E8%5C%20V)
Uniform magnetic field , B = 0.02 T .
Mass of proton ,
.
Charge on proton ,
.
Also , velocity of proton is perpendicular to magnetic field .
To Find :
The radius of the proton's resulting orbit .
Solution :
Now , when velocity is perpendicular to magnetic field radius of orbit is given by :
Putting all given values above :
![r=\sqrt{\dfrac{2\times 6.44\times 10^8\times 1.67\times 10^{-27}}{1.6\times 10^{-19}\times 0.02^2}}\\\\r=183.33 \ m](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%206.44%5Ctimes%2010%5E8%5Ctimes%201.67%5Ctimes%2010%5E%7B-27%7D%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%200.02%5E2%7D%7D%5C%5C%5C%5Cr%3D183.33%20%5C%20m)
Therefore , radius of orbit is 183.33 m .
Hence , this is the required solution .
Horizontal and Vertical are the two motions that combine to produce projectile motion.