Question

A car driving on level ground at 20.0 m/s slams on its brakes and skids to a halt. If the coefficient of kinetic friction between the car’s tires and the road is 0.750, how far does the car skid before stopping? How far would the car have skidded if it had been moving at 40.0 m/s?

Answer 1

The distance the car has skidded if it had been moving at 40.0 m/s is 27.2m

The linear force acting on the car is opposed by the frictional force. Hence;

$F=F_f$

$ma = -\mu R\\ma =-\mu mg$

m is the mass of the car

a is the acceleration

$\mu$ is the coefficient of friction

R is the normal force

Given the following parameters

$a=-\mu g$

$a =-0.75(9.8)\\a=-7.35m/s^2$

Get the distance the car has skidded if it had been moving at 40.0 m/s

$v^2=u^2+2as$

$0^2=20^2+2(-7.35)s\\0=400-14.7s\\s=\frac{400}{14.7}\\s= 27.2m$

Hence the distance the car has skidded if it had been moving at 40.0 m/s is 27.2m

Learn more here: brainly.com/question/15246552