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3 years ago

What symbol of the periodic table is Diamond?

1 answer:

6 0

Nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷

You might be interested in

Uranium – 235 has a half-life of 713 million years. Would uranium – 235 or carbon – 14 be more useful for dating Cambrian time e

kenny6666 [7]

Uranium-235 would be more useful for dating in Cambrian time because Cambrian time was 540 million years ago while the half life of carbon-14 is only 5,730 years
Hope this helps

6 0

3 years ago

Suppose you have a dozen carbon atoms, a dozen gold atoms, and a dozen iron atoms. Even though you have the same number of each,

mixer [17]

Answer:

By weight they have the same mass, but the number of atoms is different

Explanation:

3 0

3 years ago

Read 2 more answers

The wind causes this wind turbine to spin, creating electricity. The moving blades are evidence of A) solar power. B) work being

timama [110]

They answer is (C) Potential Energy

5 0

2 years ago

A particular balloon can be stretched to a maximum surface area of 1257 cm2. The balloon is filled with 3.1 L of helium gas at a

lianna [129]

Answer:

P = 0.6815 atm

Explanation:

Pressure = 754 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 754 / 760 atm = 0.9921 atm

Temperature = 294 K

Volume = 3.1 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9921 atm × 3.1 L = n × 0.0821 L.atm/K.mol × 294 K

⇒n of helium gas= 0.1274 moles

Surface are = 1257 cm²

For a sphere, Surface area = 4 × π × r² = 1257 cm²

r² = 1257 / 4 × π ≅ 100 cm²

r = 10 cm

The volume of the sphere is :

$V=\frac {4}{3}\times \pi\times r^3$

Where, V is the volume

r is the radius

$V=\frac {4}{3}\times \frac {22}{7}\times {10}^3$

V = 4190.4762 cm³

1 cm³ = 0.001 L

So, V (max) = 4.19 L

T = 273 K

n = 0.1274 moles

Using ideal gas equation as:

PV=nRT

Applying the equation as:

P × 4.19 L = 0.1274 × 0.0821 L.atm/K.mol × 273 K

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4 0

3 years ago

you are given a cube with a length of 2.5 cm a width of 2.5 and a height of 2.5cm you place it on a scale and it's mass is 295g

Rama09 [41]

Density (p) = Mass / volume

P=295/15.625

=18.88

therefore p=18.88

3 0

3 years ago