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DiKsa [7]
3 years ago
12

Blank are produced when atoms if the elements in group 7A blank an electron​

Chemistry
1 answer:
Romashka [77]3 years ago
6 0

Answer:

Halide ions are produced when atoms of elements in Group 7A gain an electron.

Explanation:

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What is the weight of:
Dafna11 [192]

Answer:

Oxygen = 15.999 g/mol

Iron = 3 × 55.845 = 167.535 g/mol

CaCO3 = 20 × 100.0869 = 2001.738 g/mol

8 0
3 years ago
CH3COOH  CH3COO– + H+
Oxana [17]

(a)

pH = 4.77

; (b)

[

H

3

O

+

]

=

1.00

×

10

-4

l

mol/dm

3

; (c)

[

A

-

]

=

0.16 mol⋅dm

-3

Explanation:

(a) pH of aspirin solution

Let's write the chemical equation as

m

m

m

m

m

m

m

m

l

HA

m

+

m

H

2

O

⇌

H

3

O

+

m

+

m

l

A

-

I/mol⋅dm

-3

:

m

m

0.05

m

m

m

m

m

m

m

m

l

0

m

m

m

m

m

l

l

0

C/mol⋅dm

-3

:

m

m

l

-

x

m

m

m

m

m

m

m

m

+

x

m

l

m

m

m

l

+

x

E/mol⋅dm

-3

:

m

0.05 -

l

x

m

m

m

m

m

m

m

l

x

m

m

x

m

m

m

x

K

a

=

[

H

3

O

+

]

[

A

-

]

[

HA

]

=

x

2

0.05 -

l

x

=

3.27

×

10

-4

Check for negligibility

0.05

3.27

×

10

-4

=

153

<

400

∴

x

is not less than 5 % of the initial concentration of

[

HA

]

.

We cannot ignore it in comparison with 0.05, so we must solve a quadratic.

Then

x

2

0.05

−

x

=

3.27

×

10

-4

x

2

=

3.27

×

10

-4

(

0.05

−

x

)

=

1.635

×

10

-5

−

3.27

×

10

-4

x

x

2

+

3.27

×

10

-4

x

−

1.635

×

10

-5

=

0

x

=

1.68

×

10

-5

[

H

3

O

+

]

=

x

l

mol/L

=

1.68

×

10

-5

l

mol/L

pH

=

-log

[

H

3

O

+

]

=

-log

(

1.68

×

10

-5

)

=

4.77

(b)

[

H

3

O

+

]

at pH 4

[

H

3

O

+

]

=

10

-pH

l

mol/L

=

1.00

×

10

-4

l

mol/L

(c) Concentration of

A

-

in the buffer

We can now use the Henderson-Hasselbalch equation to calculate the

[

A

-

]

.

pH

=

p

K

a

+

log

(

[

A

-

]

[

HA

]

)

4.00

=

−

log

(

3.27

×

10

-4

)

+

log

(

[

A

-

]

0.05

)

=

3.49

+

log

(

[

A

-

]

0.05

)

log

(

[

A

-

]

0.05

)

=

4.00 - 3.49

=

0.51

[

A

-

]

0.05

=

10

0.51

=

3.24

[

A

-

]

=

0.05

×

3.24

=

0.16

The concentration of

A

-

in the buffer is 0.16 mol/L.

hope this helps :)

6 0
2 years ago
Can someone help me lol;)<br> WILL MARK BRAINLIEST
inn [45]

Answer:

See explanation

Explanation:

1 ) Al has physical and chemical properties, similar to Boron, because It's also part of group 13, also called the boron group. The elements are characterized by having three valence electrons.

2) Lithium is in group 1. This means it has 1 valence electron.

Nitrogen has 7 electrons. The first shell can only have 2 electrons, so the second and outer shell has 5 electrons. Those 5 electrons are the 5 valence electrons;

Neon is a noble gas, it's in the stable noble gas configuration. This means it has 8 valence electrons.

Oxygen = non-metal because it's a gas

Silicon = metalloid

Helium = non-metal because it's a gas

Arsenic = metalloid

Sodium = it's an (alkali) metal, It is physically silver colored and is a soft metal of low density. Pure sodium is not found naturally on earth because it is a highly reactive metal

Chlorine = non-metal

Tin = Is a soft,  ductile and highly crystalline silvery-white metal

Boron = it does conduct electricity. Its chemical properties are mostly, but not entirely, and non-metallic

lead = is a heavy metal that is denser than most common materials

Radon = metalloid

Cesium = It is a soft, silvery-golden alkali metal

Carbon = non metal

Period

⇒ Horizontal from left to right

⇒ same number of atomic orbitals

⇒period = row

Group

⇒ vertical colums

⇒same number of valence electrons

⇒ same physical and chemical properties

4 0
4 years ago
Calculate the molecular mass of Al2(SO4)3(Molecular mass of Al=27, S=32, O=16) Pls fast
Whitepunk [10]

Al₂(SO₄)₃

= 2.Al+3.S+12.O

= 2.27 + 3.32+12.16

= 54+96+192

=342 g/mol

8 0
2 years ago
Why alkali metals easly ionize
Dmitriy789 [7]
Here’s what I found:

It takes very little energy to remove that outermost electron from an alkali metal. Thus, alkali metals easily lose their outermost electron to become a +1 ion. ... In fact, as you go down the 1A column, the first ionization energies get lower and lower, making cesium the most easily ionized element on the periodic table.

So basically it’s because part of what makes alkali metals so reactive is that they have one electron in their outermost electron layer.
7 0
3 years ago
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