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den301095 [7]
3 years ago
10

Give the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each element:_____

___. a. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 b. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 c. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 d. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p8e. None of these
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
7 0

The question is incomplete, here is the complete question:

Give the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each element: (a) P, (b)  Mg,  (c) Se

<u>Answer:</u>

<u>For a:</u> The electronic configuration of the monoatomic ion formed is 1s^22s^22p^63s^23p^6

<u>For b:</u> The electronic configuration of the monoatomic ion formed is 1s^22s^22p^6

<u>For c:</u> The electronic configuration of the monoatomic ion formed is 1s^22s^22p^63s^23p^64s^23d^{10}4p^6

<u>Explanation:</u>

An ion is formed when a neutral atom looses or gains electrons.

  • When an atom looses electrons, it results in the formation of positive ion known as cation.
  • When an atom gains electrons, it results in the formation of negative ion known as anion.

For the given elements:

(a) Phosphorus

This is the 15th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^3

This element will gain 3 electrons to form P^{3-} ion

The electronic configuration of the monoatomic ion formed is 1s^22s^22p^63s^23p^6

(b) Magnesium

This is the 12th element of the periodic table having electronic configuration of 1s^22s^22p^63s^2

This element will loose 2 electrons to form Mg^{2+} ion

The electronic configuration of the monoatomic ion formed is 1s^22s^22p^6

(c) Selenium

This is the 34th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^4

This element will gain 2 electrons to form Se^{2-} ion

The electronic configuration of the monoatomic ion formed is 1s^22s^22p^63s^23p^64s^23d^{10}4p^6

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What happens to electrons in ionic bonds?
vlabodo [156]

Answer:

Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

Hope this helps :)

3 0
3 years ago
Which liquid has the highest vapor pressure at 75°C?
Temka [501]

Answer:

1)  Ethanol

Explanation:

If we will have <u>interactions</u> we will need more <u>energy</u> to break them in order to go from liquid to gas. If we need more <u>energy</u>, therefore, the <u>temperature will be higher</u>.

In this case, we can discard the <u>propanone</u> because this molecule don't have the ability to form <u>hydrogen bonds</u>. (Let's remember that to have hydrogen bonds we need to have a hydrogen bond to a <u>heteroatom</u>, O, N, P or S).

Then we have to analyze the hydrogen bonds formed in the other molecules. For ethanol, we will have only <u>1 hydrogen bond</u>. For water and ethanoic acid, we will have <u>2 hydrogen bonds</u>, therefore, we can discard the ethanol.  

For ethanoic acid, we have 2 <u>intramolecular hydrogen bonds</u>. For water we have 2 <u>intermolecular hydrogen bonds</u>, therefore, the strongest interaction will be in the <u>ethanoic acid</u>.

The<u> closer boiling point</u> to the 75ºC is the <u>ethanol</u> (boiling point of 78.8 ºC) therefore these molecules would have <u>enough energy</u> to <u>break</u> the hydrogen bonds and to past from<u> liquid to gas</u>.

4 0
2 years ago
Ag2S + Al(s) = Al2S3 + Ag(s) (unbalanced)
Dovator [93]

Answer:

1. 0.97 V

2. Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/Ag_(_s_)

Explanation:

In this case, we can start with the <u>half-reactions</u>:

Ag^+~_(_a_q_)->~Ag_(_s_)

Al_(_s_)~->~Al^+^3~_(_a_q_)

With this in mind we can <u>add the electrons</u>:

Ag^+~_(_a_q_)+~e^-~->~Ag_(_s_)  <u>Reduction</u>

Al_(_s_)~->~Al^+^3~_(_a_q_)+~3e^-~ <u>Oxidation</u>

The reduction potential values for each half-reaction are:

Ag_2S~+~e^-~->~Ag_(_s_)~+~S^-^2~_(_a_q_) - 0.69 V

Al^+^3~_(_a_q_)+~2e^-~->~Al_(_s_) -1.66 V

In the aluminum half-reaction, we have an oxidation reaction, therefore we have to <u>flip</u> the reduction potential value:

Al_(_s_)~->~Al^+^3~+~2e^-~ +1.66 V

Finally, to calculate the overall potential we have to <u>add</u> the two values:

1.66 V - 0.69 V = <u>0.97 V</u>

For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:

Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/~Ag_(_s_)

I hope it helps!

3 0
3 years ago
A student drops some metal paper clips in a box of sand. The student uses a magnet to separate the metal paper clips from the sa
Dmitriy789 [7]

Answer:

compound

Explanation:

because now there are one together

3 0
2 years ago
How would you know if a precipitate was formed without performing the chemical reaction
Goshia [24]
Hey there

Thats easy

Precipitation occurs when cations and anions in aqueous solution combine to form an insoluble ionic compound called precipitation. So, you can refer to a solubility chart or draw polar/nonpolar lewis structures, that might be helpful.
Remember water is polar so polar molecules will dissolve in water 
4 0
3 years ago
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