3 years ago

A boy jumps on his bed. when his feet push the bed down, what is the reaction force

Physics

1 answer:

deff fn [24]3 years ago

8 0

Answer:

the bed pushes his fee t up

Explanation:

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$331665750000\ m/s^2$

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G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

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u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

$g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2$

The gravitational acceleration at the surface of such a star is $331665750000\ m/s^2$

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s$

The velocity of the object would be 3257806.62409 m/s

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