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pav-90 [236]
3 years ago
11

John bought 85 tickets to use at the carnival. He used some of the tickets to ride the bumper cars and play some games. Now he h

as 15 tickets left. What is the percent decrease in the number of tickets that he has? Please do a step by step explanation! thank you!​
Mathematics
1 answer:
qwelly [4]3 years ago
7 0
Bbbbghjjn. Yhiiibbhhb chunking. Hiiiiihgfyh. I be huh
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10x^3 y^-5 z^-2 if x=3 y=2 and z=5 express your answer as a reduced fraction
sineoko [7]

Answer:

\large\boxed{\dfrac{27}{80}}

Step-by-step explanation:

Put x = 3, y = 2 and z = 5 to the given expression 10x^3y^{-5}z^{-2}:

10(3^3)(2^{-5})(5^{-2})\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{10(27)}{(2^5)(5^2)}=\dfrac{270}{(32)(25)}=\dfrac{270}{800}=\dfrac{27}{80}

7 0
3 years ago
(I WILL MARK BRAINLY)
Mademuasel [1]

Answer:

Step-by-step explanation:

light blue, 4,6,8

5 0
3 years ago
PLSS HELPP WILL GIVE BRAINLIEST PLS ANSWER ALL 3
podryga [215]

Answer:

\large \boxed{\sf non \ linear, \ non \ linear, \ linear, \ linear}

Step-by-step explanation:

Write the equations in the form y = mx + b

If the equation contains exponents then it is non-linear, if not then it is linear.

2xy = 3

This graph forms a curve so it is non-linear

y = 1x³ + 5

This equation is non-linear because it contains an exponent

y = x/3

y = 1/3x + 0

This equation is linear ( no exponent(s) )

2y = 1/2x

y = 1/4x + 0

This equation is linear ( no exponent(s) )

5 0
3 years ago
A cube and a net of the cube are shown. The edge length of the cube is labeled 5 centimeters. The net consists of 4 squares conn
Natasha_Volkova [10]

We will determine the surface area as follows:

A=6(5cm\ast5cm)\Rightarrow A=150cm^2

So, the total surface area is 150 cm^2.

4 0
1 year ago
Can somebody please help me with this question?!?!?!
scoray [572]
I don't think there's any answer. It says that the absolute value of x-7 is negative 2, but an absolute value is always positive. So there's no value for x that can make the equation a true statement.
6 0
3 years ago
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