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2 years ago

An ice cube weighs 20 grams. How much will it weigh after it melts?

Mathematics

1 answer:

attashe74 [19]2 years ago

5 0

Answer:

= 40.32 cm = 15.87 inches

Step-by-step explanation:

Does an ice cube weigh the same when melted? - Quora. , Energy Analyst and “Futurist”. Obviously, the mass of the water is the same as the ice from whence it came, assuming no evaporation. However, the volume shrank as it melted; became more dense, and therefore displaced less air.

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Add.<br> 3 7/11 + 9 6/11<br> Write your answer as a mixed number in simplest form.<br><br> Help

Vilka [71]

Answer:

13 2/11

Step-by-step explanation:

40/11+105/11

145/11

13 2/11

7 0

2 years ago

Read 2 more answers

What is the decimal multiplier to increase by 3%?

nlexa [21]

If you want to increase something by 3%, you would ADD 100% to it, so:
3% + 100% = 103%
Then you divide it by 100 to turn it into a decimal, so:
103% / 100 = 1.03
So to increase by 3%, the multiplier would be 1.03

If you wanted to decrease by 3%, you would SUBTRACT 100% from 3%, so:
100% - 3% = 97%
And then you would divide 97% by 100 to turn it into a decimal (multiplier), so:
97% / 100 = 0.97
So to decrease by 3%, the multiplier would be 0.97

7 0

2 years ago

PLEASE HELP ITS MATH THANK YOUUUU

Greeley [361]

Answer:

1 inch

Step-by-step explanation:

Equation:

2/9.4 = x/4.7

9.4 = 9.4x

x = 1

-Chetan K

7 0

2 years ago

100 POINTSSS! ASAP ANSWEERR PLS

Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = $\frac{FV-SV}{SV}*100$ (FV = final value, SV = starting value)

Percentage increase = $\frac{1.4214 - 0.7107}{0.7107}*100$

Percentage increase = $\frac{0.7107}{0.7107}*100$

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = $\frac{10,201-10,100}{10,100}*100$

= $\frac{101}{10,100}*100$

= 0.01 * 100

= 1 %

PC of product B from 2nd to 3rd year = $\frac{10,303.01-10,201}{10,201} *100$

= 1%

PC of product B from 3rd to 4th year $=\frac{10,406.04-10,303.01}{10,303.01}*100$

≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0

3 years ago

A track and field playing area is in the shape of a rectangle with semicircles at each end . The perimeter of the track is to be

MAVERICK [17]

We can let the radius of the semi circles be r and x can be the length of the rectangle.
The perimeter will be Perimeter = 2x + 2pr = 1200
The area of the rectangle is Area = x(2r)
Once we solve the perimeter equation, you get x = 600.
Put this into the area equation and you get Area = (600 - pr)(2r)
The maximum then gives r = 95. 493 and area 57, 295.8
Dimensions

Height is twice the radius or 190.986. Find base use equation x = 600 - p(95.493) = 300.

This means dimensions are 300 by 190.986

5 0

3 years ago