Answer:
Explanation:
Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:
and filling in:
which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:
a = -9.8 m/s/s
t = 2.8 seconds
Δx = ?? m
The one-dimensional motion equation that utilizes all of these variables is
Δx = 
and filling in:
Δx = 
I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have
Δx = 27 + 
and then to the right of the + sign and to 2 significant digits we have
Δx = 27 - 38 so
Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.
Answer:
Expression of work done is
Work done to move the sled is given as 1.94 J
Explanation:
As we know that the formula of work done is given as
here we know that
F = 6 N
d = 0.4 m
so we will have
Answer:
Explanation:
The Joule-Thomson coefficient is the ratio of the change of temperature to the change of pressure under isoenthalpic conditions:
Initial and final properties are:
. Superheated Vapor.
. Superheated Vapor.
The Joule-Thomson coefficient is approximately:
Answer:
20m
6.9s
Explanation:
The vertical velocity of the ball is 20m/s. We can calculate the kinetic energy which gets transferred to potential energy once it gets to the top.
we can subtitute v = 20m/s and g = 10m/s2
So the ball could go 20m high from the child hand, or 120m fro the bottom of the cliff.
The time it takes for the ball to travels to the top is the time it takes for it to decelerate from 20m/s to 0m/s with gravitational deceleration g = 10m/s2
t = v / g = 20 / 10 = 2s
Then the ball will start accelerating down ward with a constant acceleration of g = 10m/s. In order to cover distance d of 120m from the top to the bottom of the cliff
So the total time it takes is 4.9 + 2 = 6.9s
The molecules making up object collide with the molecules of the other and some of the kinetic energy from a warmer object is transferred to the cooler one.
