Answer:
Explanation:
As we know that the magnitude of electric field intensity is given as
now we know that intensity of the wave is given as the product of energy density and speed of the wave
so intensity is the energy flow per unit area per unit of time
so the energy that flows through the area of 0.0259 m^2 in 11.7 s is given as
Answer: D
Explanation:
Kinetic energy = 1/2mV^2
From the formula above, we can deduce that kinetic energy is proportional to the square of speed. That is,
K.E = V^2
Graphically, the relationship isn't linear but a positive exponential. Therefore, option D is the correct answer.
The working equation for this is: E = F/Q, where E is the strength of electric field, F is the force and Q is the charge. The force is equal to:
F = mg = (0.13/1000 kg)(9.81 m/s²) = 1.2753×10⁻³ N
The charge of he excess electrons is equal to:
Q = (-1.6021766208×10⁻¹⁹ C/electron)(1×10¹⁰ electrons)
Q = -1.6021766208×10⁻⁹ C
E = 1.2753×10⁻³ N/-1.6021766208×10⁻⁹ C
E = -795,979.66 N/C
Answer:
The necessary criterion to validate the PTSD (posttraumatic stress disorder) is criterion A, (one required): the person was exposed to: death, threatened death, actual or threatened serious injury, or actual or threatened sexual violence,one symptom (or more): inability to remember an important aspect of the event, from criterion B, one symptom (or more): wars survivors, persistent and exaggerated negative beliefs about oneself, others, or the world, and persistent negative emotional state.to criterion C: old age abused; persistent distorted cognitions about the cause or consequences of the event.
Explanation:
DSM-5 PTSD diagnosis measures, assesses, or evaluates dissociative subtypes, which causes disconnection from the surrounding world or from oneself.
The DSM-5 manual, for the PTSD diagnosis, includes the DSM-IV/ICD-9 309.81 to the ICD-10 F43.10.
An experienced mental health provider, such as a psychiatrist or psychologist, is generally in charge of the diagnosis.
To be diagnosed with PTSD, an adult must have at least one avoidance symptom re-experiencing symptom for at least 1 month.
Answer:
B) The same as the momentum change of the heavier fragment.
Explanation:
Since the initial momentum of the system is zero, we have
0 = p + p' where p = momentum of lighter fragment = mv where m = mass of lighter fragment, v = velocity of lighter fragment, and p' = momentum of heavier fragment = m'v' where m = mass of heavier fragment = 25m and v = velocity of heavier fragment.
0 = p + p'
p = -p'
Since the initial momentum of each fragment is zero, the momentum change of lighter fragment Δp = final momentum - initial momentum = p - 0 = p
The momentum change of heavier fragment Δp' = final momentum - initial momentum = p' - 0 = p' - 0 = p'
Since p = -p' and Δp = p and Δp' = -p = p ⇒ Δp = Δp'
<u>So, the magnitude of the momentum change of the lighter fragment is the same as that of the heavier fragment. </u>
So, option B is the answer
