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Sonbull [250]
2 years ago
8

Please can someome answer this question with working out​

Physics
2 answers:
deff fn [24]2 years ago
7 0

Answer: Yess, why not

Explanation:

I think I just answered this question

Murljashka [212]2 years ago
3 0
What is the question? I can’t see it?
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To practice Problem-Solving Strategy 16.1 Standing waves. An air-filled pipe is found to have successive harmonics at 800 HzHz ,
bazaltina [42]

Answer:

Length of the pipe = 53.125 cm

Explanation:

given data

harmonic frequency f1  = 800 Hz

harmonic frequency f2  = 1120 Hz

harmonic frequency f3  = 1440 Hz

solution

first we get here fundamental frequency that  is express as

2F = f2 - f1    ...............1

put here value

2F = 1120 - 800

F = 160 Hz

and

Wavelength is express as

Wavelength  = Speed ÷ Fundamental frequency    ................2

here speed of waves in air  = 340 m/s

so put here value

Wavelength  =340 ÷ 160

Wavelength   = 2.125 m

so

Length of the pipe will be

Length of the pipe = 0.25 × wavelength    ......................3

put here value

Length of the pipe = 0.25 × 2.125

Length of the pipe = 0.53125 m

Length of the pipe = 53.125 cm

7 0
3 years ago
On a grid, what is the distance between two points located at (1, 1) and (8, 4) roughly equal to?
Diano4ka-milaya [45]
Ithink the answer is a
5 0
4 years ago
A hydrogen atom has its electron in the n = 6 level. the radius of the electron's orbit in the bohr model is 1.905 nm.
gayaneshka [121]
Are there any options or is it not multiple choice.
5 0
3 years ago
A scientist suspends a spring from a force sensor. She then pulls on the spring causing the spring to stretch 1.0 cm. She record
Nadusha1986 [10]
This situation describes the Hooke's Law which states that "When an elastic object - such as a spring - is stretched, the increased length is called its extension. The extension of an elastic object is directly proportional to the force applied to it". The formula is <span>F = k × e , F for the force, k for spring constant expressed in N/m, e for extension in m. This equation works for as long the spring is not stretch too much because once it exceeded its limit, the spring will not return to its original length the moment the load is removed.</span>
8 0
3 years ago
If μs is greater than some critical value, the woman cannot start the crate moving no matter how hard she pushes. calculate this
fiasKO [112]

weight = mg acts downwards <span>
normal force = N acts upwards. 
and force F acts at an angle θ below the horizontal. 
(Let us assume that the woman pushes from the left, so F is acted towards the right, which is below the horizontal) 
so that, Frictional force, f=us*N acts towards the left 

Now we balance the forces along x and y directions: 
y direction: N = mg + F sinΘ 
x direction: us * N = F cosΘ 

We let the value of µs be equal to a value such that any F will not be able to move the crate. Then, if we increase F by an amount F', then the force pushing the crate towards the right also increases by F' cosΘ. Additionally, the frictional force f must raise by exactly this amount. 
Since f can’t exceed us*N, so the normal force must increase by F' cosΘ/us. 
Also, from the y direction equation, the normal force exceeds by F' sin Θ. 

<span>These two values must be the same, therefore:
<span>us = cot θ</span></span></span>

4 0
3 years ago
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