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LenaWriter [7]
2 years ago
15

Idetify 5 types of kitchen tool Whrite the difinition of each tool.​

Physics
1 answer:
Vilka [71]2 years ago
4 0
Answer for 5 kitchen tools

(1) wooden spoon - often made from bamboo, is used for mixing and when cooking and stirring hot foods. A wooden spoon will not transfer heat to the hand like a metal spoon.

(2) wire whisk - many wire loops held together in a handle - used to whip eggs or cream or add air to a thin batter.

(3) rubber scraper - A smooth rubber flat spoon on a handle, Used for mixing, folding soft ingredients and to scrape ingredients from a bowl.

(4) peeler - sharp curved metal scraper in a handle - Used to remove the outer layer of fruits and vegetables.

(5) Paring knife - small knife that fits in the hand. It’s an all purpose small knife used for small cuts, garnishes, paring or coring.

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What is the correct path of sperm cells through the male reproductive system?

Epididymis, seminiferous tubules, urethra, vas deferens

<u>Seminiferous tubules, epididymis, vas deferens, urethra </u>

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Hope this helps :)

Have a great day !

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Explanation:

8 0
2 years ago
(I) In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second pro
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Answer:

The second projectile was 1.41 times faster than the first.

Explanation:

In the ballistic pendulum experiment, the speed (v) of the projectile is given by:  

v = \frac{m + M}{m} \cdot \sqrt{2gh}

<em>where m: is the mass of the projectile, M: is the mass of the pendulum, g: is the gravitational constant and h: is the maximum height of the pendulum.   </em>

To know how many times faster was the second projectile than the first, we need to take the ratio for the velocities for the projectiles 2 and 1:    

\frac{v_{2}}{v_{1}} = \frac{\frac{m_{2} + M}{m_{2}} \cdot \sqrt{2gh_{2}}}{\frac{m_{1} + M}{m_{1}} \cdot \sqrt{2gh_{1}}}           (1)

<em>where m₁ and m₂ are the masses of the projectiles 1 and 2, respectively, and h₁ and h₂ are the maximum height reached by the pendulum by the projectiles 1 and 2, respectively.  </em>

Since the projectile 1 has the same mass that the projectile 2, we can simplify equation (1):

\frac{v_{2}}{v_{1}} = \frac{\sqrt{h_{2}}}{\sqrt{h_{1}}}  

\frac{v_{2}}{v_{1}} = \frac{\sqrt{5.2 cm}}{\sqrt{2.6 cm}}

\frac{v_{2}}{v_{1}} = 1.41  

Therefore, the second projectile was 1.41 times faster than the first.  

I hope it helps you!

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