3 years ago

Sh0w b00bs .ID: 398 609 0399P: 1234

Mathematics

2 answers:

Llana [10]3 years ago

6 0

Answer:

excuse me................

slava [35]3 years ago

4 0

What the…………………..
Whatt

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Eliminate the parameter,t, in the parametric equation, x=6cos t, and y =3 sin t

german

X = 6 cos(t)
y = 3 sin(t)

we can rewrite these equations as:

$\frac{x}{6}=cost(t) \\ \\ \frac{y}{3} =sin(t)$

Taking squares of both equations we get:

$( \frac{x}{6})^{2}=sin^{2} (t) \\ \\ 
( \frac{y}{3})^{2}=cos^{2}(t)$

Adding both the equations, we get:

$\frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=sin^{2}(t)+cos^{2}(t) \\ \\ 
 \frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=1$

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Liono4ka [1.6K]

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