All categories

3 years ago

Kết luận nào sau đây là đúng khi nói về hiệu điện thế giữa hai đầu đoạn mạch mắc nối tiếp ?

Physics

1 answer:

Lapatulllka [165]3 years ago

3 0

Answer:

abe tera q kya he?? can't understand ur language dude

You might be interested in

What are the two factors that determine the density of water mass?

BigorU [14]

Temperature and salinity

5 0

4 years ago

If a sinusoidal electromagnetic wave with intensity 18 W/m2 has an electric field of amplitude E, then a 36 W/m2 wave of the sam

Neporo4naja [7]

Answer:

The correct option is D

Explanation:

From the question we are told that

The intensity of the first electromagnetic wave is $I = 18 \ W/m^2$

The amplitude of the electric field is $E_{max}_1 =A$

The intensity of the second electromagnetic wave is $I = 36 \ W/m^2$

Generally the an electromagnetic wave intensity is mathematically represented as

$I = \frac{1}{2} * \epsilon_o * c * E_{max}^2$

Looking at this equation we see that

$I \ \ \alpha \ \ E^2_{max}$

=> $\frac{I_1}{I_2} = [ \frac{ E_{max}_1}{ E_{max}_2} ] ^2$

=> $E_{max}_2 = \sqrt{\frac{x}{y} } * E_{max}_1$

=> $E_{max}_2 = \sqrt{\frac{36}{18} } * E$

=> $E_{max}_2 = \sqrt{2 } E$

5 0

3 years ago

Fossil fuels store energy from the sun as<br><br> question 5

qwelly [4]

Answer:

Fossil fuels store energy from the sun as

Explanation:

3 0

3 years ago

A 2.4-kg cart is rolling along a frictionless, horizontal track towards a 1.7-kg cart that is held initially at rest. The carts

inessss [21]

Answer:

Explanation:

Mass of first cart M1=2.4kg

Velocity of first cart U1=4.1m/s

Mass of second cart M2=1.7kg

Second cart is initially at rest U2=0

After an instant, the velocity of the second cart is U2=-2.8m/s

Now after collision the two cart move together with the same velocity I.e inelastic collision

Using conservation of momentum

Momentum before collision, = momentum after collision

M1U1 + M2U2 = (M1+M2)V

2.4×4.1 + 1.7× -2.8 =(2.4+1.7)V

9.84 - 4.76 = 4.1V

5.08=4.1V

V=5.08/4.1

V=1.24m/s

The momentum of the two cart at that instant is

M1U1+M2U2

2.4×4.1 + 1.7× -2.8

9.84 - 4.76

5.08kgm/s

So the momentum at the instant the velocity is 4.1m/s for cart 1 and -2.8m/s for cart 2 is 5.08kgm/s

3 0

3 years ago

A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a

damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0

3 years ago