Answer:
the speed of light in air is about 299,000,000 and 3×10⁸ m/s
<span>3598 seconds
The orbital period of a satellite is
u=GM
p = sqrt((4*pi/u)*a^3)
Where
p = period
u = standard gravitational parameter which is GM (gravitational constant multiplied by planet mass). This is a much better figure to use than GM because we know u to a higher level of precision than we know either G or M. After all, we can calculate it from observations of satellites. To illustrate the difference, we know GM for Mars to within 7 significant figures. However, we only know G to within 4 digits.
a = semi-major axis of orbit.
Since we haven't been given u, but instead have been given the much more inferior value of M, let's calculate u from the gravitational constant and M. So
u = 6.674x10^-11 m^3/(kg s^2) * 6.485x10^23 kg = 4.3281x10^13 m^3/s^2
The semi-major axis of the orbit is the altitude of the satellite plus the radius of the planet. So
150000 m + 3.396x10^6 m = 3.546x10^6 m
Substitute the known values into the equation for the period. So
p = sqrt((4 * pi / u) * a^3)
p = sqrt((4 * 3.14159 / 4.3281x10^13 m^3/s^2) * (3.546x10^6 m)^3)
p = sqrt((12.56636 / 4.3281x10^13 m^3/s^2) * 4.458782x10^19 m^3)
p = sqrt(2.9034357x10^-13 s^2/m^3 * 4.458782x10^19 m^3)
p = sqrt(1.2945785x10^7 s^2)
p = 3598.025212 s
Rounding to 4 significant figures, gives us 3598 seconds.</span>
Answer:
Weight
a) weight's vertical component = Normal upward force
b) weight's horizontal component = Friction force = (mass of ball)(acceleration)
These forces depend upon the track,
1) inclined or horizontal
2) steepness.
Explanation
The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the weight which points along the direction of the ball's motion can accelerate the ball.
weight's horizontal component = Friction force = (mass of ball)(acceleration)
The other component pushes the ball into the ramp, and the ramp pushes back.
If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. Hope this helps. Can u give me brainliest
Explanation:
Answer:
Explanation:
*Assume the parallel disks have equal diameters.
Given the electric strength as 
transferring 
electrons, the disk's Area can be calculated using the formula:
#We now calculate the disks diameter:
Hence, the diameter of the disks is
The centripetal acceleration is 
Explanation:
For an object in uniform circular motion, the centripetal acceleration is given by
where
v is the speed of the object
r is the radius of the circle
The speed of the object is equal to the ratio between the length of the circumference (
) and the period of revolution (T), so it can be rewritten as
Therefore we can rewrite the acceleration as
For the particle in this problem,
r = 2.06 cm = 0.0206 m
While it makes 4 revolutions each second, so the period is
Substituting into the equation, we find the acceleration:
Learn more about centripetal acceleration:
brainly.com/question/2562955
#LearnwithBrainly
