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Mumz [18]
1 year ago
5

What is a human endeavor

Physics
2 answers:
galina1969 [7]1 year ago
8 0

Answer:

Education is a human endeavor. it prepares the individual for life and for the future.

Explanation:

perhaps we can say that a "human endeavor" is one in which humans strive to achieve something of significance, or something of significance which only can be achieved via human intelligence.

Scilla [17]1 year ago
3 0
A human endeavor is one in which humans strive to achieve something of significance, or something of significance which can only be achieved via human intelligence, ingenuity, and/or willpower. Or simply a person’s motivation or drive to complete something.
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How much work is done using a 500 W microwave for 5 minutes
frosja888 [35]

Power = work done/time

work done = power x time

                  = 500x5x60

                  = 150000J

6 0
3 years ago
baseball is hit into the air at an initial speed of 37.2 m/s and an angle of 49.3 ° above the horizontal. At the same time, the
Agata [3.3K]

Answer:

The average speed of the fielder is 5.24 m/s

Explanation:

The position vector of the ball after it was hit can be calculated using the following equation:

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α + 1/2 · g · t²)

Where:

r = position vector at time t.

x0 = initial horizontal position.

v0 = initial velocity.

t = time.

α = launching angle.

y0 = initial vertical position

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem.

When the ball is caught, its position vector will be (see r1 in the figure):

r1 = (r1x, 0.873 m)

Then, using the equation of the position vector written above:

r1x = x0 + v0 · t · cos α

0.873 m = y0 + v0 · t · sin α + 1/2 · g · t²

Since the frame of reference is located at the point where the ball was hit, x0 and y0 = 0. Then:

r1x = v0 · t · cos α

0.873 m = v0 · t · sin α + 1/2 · g · t²

Let´s use the equation of the y-component of r1 to obtain the time of flight of the ball:

0.873 m = 37.2 m/s · t · sin 49.3° - 1/2 · 9.8 m/s² · t²

0 = -0.873 m + 37.2 m/s · t · sin 49.3° - 4.9 m/s² · t²

Solving the quadratic equation:

t = 0.03 s and t = 5.72 s.

It would be impossible to catch the ball immediately after it is hit at t = 0.03 s. Besides, the problem says that the ball was caught on its way down. Then, the time of flight of the ball is 5.72 s.

With this time, we can calculate r1x which is the horizontal distance traveled by the ball from home:

r1x = v0 · t · cos α

r1x = 37.2 m/s · 5.72 s · cos 49.3°

r1x = 1.39 × 10² m

The distance traveled by the fielder is (1.39 × 10² m - 1.09 × 10² m) 30.0 m.

The average velocity is calculated as the traveled distance over time, then:

average velocity = treveled distance / elapsed time

average velocity = 30.0 m / 5.72 s = 5.24 m/s

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the Answer is 91  meters

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A 1.0 kg rock moving at 8.4 m/s will have ______ of kinetic energy
BlackZzzverrR [31]
K.E=1/2mv^2 K.E=1/2multiply1multiply8^2=32joules
4 0
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If 6.24×10¹⁸ electron pass through a wire in 1s how many pass through it during a time interval of 2hr, 47min and 10s
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Answer = 6.24x10^18 x ((2 x 3600) + (47 x 60) + 10)
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