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charle [14.2K]
2 years ago
7

Choose ALL of the transformations that have been applied to the linear function below.

Mathematics
1 answer:
alex41 [277]2 years ago
8 0
Im so sorry! I wish I could help but you don’t seem to have a image that shows the linear function
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Which of the following are solutions to the equation below?
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B and E are correct.
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6 = -4x + y<br> -5x - y = 21<br> Please Help Fast!!!!!! Substitution
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Answer:

y = 4x + 6

-5x - 4x - 6 = 21

-9x - 6 = 21

-9x = 27

x = -3

y - 4(-3) = 6

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(-3, -6)

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32 hours and 55 minutes

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Is the relationship between the number of movie tickets and the total cost of the tickets proportional?
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3 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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