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4 years ago

Why does the frequency change and wavelength not change in an instrument?

1 answer:

4 0

As wavelentgh=velocity/frequency if the frequency is changed maybe the speed of that wave changed(increased/decreased) so wavelength is constant

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A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated with 0.0950MNaOH. The acid req

bezimeni [28]

in a monoprotic acid , its capable of dissociating 1 H⁺ ion . The base used is NaOH which is capable of giving out 1 OH⁻ ion.

Therefore both base and acid react in a 1:1 molar ratio, that means for each 1 mol of monoprotic acid there is , it requires 1 mol of NaOH to be neutralised.

So at equivalence point the number of acid moles present should react with an equal number of NaOH moles to be neutralised

number of NaOH moles added - concentration x volume

number of NaOH moles - 0.0950 mol/dm³ x 27.4 x 10⁻³ dm³ = 0.00260 mol

since molar ratio of NaOH to Acid is 1:1

number of acid moles present is also - 0.00260 mol

mass of acid added - 0.2140 g

we can find molar mass using following equation

molar mass = mass / number of moles

molar mass = 0.2140 g / 0.00260 mol = 82.3 g/mol

therefore molar mass of monoprotic acid is 82.3 g/mol

8 0

4 years ago

3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que

Eduardwww [97]

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

$x=\frac{v_{i}^{2}sin(2\alpha)}{g}$ (1)

Donde:

v(i) es la velocidad inicial del cañon (82 m/s)
α es el ángulo de tiro
g es la gravedad (9.81 m/s²)
x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

$sin(2\alpha)=\frac{xg}{v_{i}^{2}}$

$sin(2\alpha)=\frac{560*9.81}{82^{2}}$

$sin(2\alpha)=0.82$

$\alpha=\frac{sin^{-1}(0.82)}{2}$

$\alpha=27.39^{\circ}$

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

$v_{x}=\frac{x}{t}$

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

$v_{i}cos(\alpha)=\frac{x}{t}$

$t=\frac{x}{v_{i}cos(\alpha)}$

$t=\frac{560}{82cos(27.39)}$

$t=7.69\: s$

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

3 0

3 years ago

The voltage across a 5-uF capacitor is: v (t )equals 10 cos open parentheses 6000 t close parentheses space straight V. What is

mamaluj [8]

Answer:

- 0.3sin6000t A

Explanation:

Voltage, v = 10 cos 6000t V

Capacitance = 5-uF

Current flowing through, i(t)

i(t) = c * d/dt (V)

c = 5-uF = 5 * 10^-6 F

i(t) = (5 * 10^-6) * d/dt(10 cos 6000t)

d/dt(10 cos 6000t) = (10 * 6000) * (-sin 6000t)

Hence,

i(t) = (5*10^-6) * (10*6000) * (-sin 6000t)

i(t) = 5*10^-6 * 6*10^4 * - sin6000t

i(t) = 30 * 10^-2 * - sin6000t

i(t) = 0.3*-sin6000t

i(t) = - 0.3sin6000t Ampere

4 0

3 years ago

In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added

amid [387]

Answer:

187 J

Explanation:

First Law of Thermodynamics :

ΔQ = ΔW + ΔU

ΔQ : Heat. If it added to system then positive and if it is rejected by system then negative.

ΔW : Work. If it done by the system then positive and if it is done on system then negative.

ΔU : Internal Energy. If it positive then temperature of system increased and if it is negative then temperature of system decreased.

ΔQ = 79 J

ΔW = - 108 J

ΔU = ?

substituting the value in the equation:

79 = -108 + ΔU

∴ ΔU = 187 J

7 0

4 years ago

Protons are found only in the atomic nucleus.<br> TRUE<br> FALSE

timama [110]

Answer:True

Explanation:

4 0

3 years ago

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