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tester [92]
2 years ago
7

Write an equation of the parabola that passes through the point (62,-490) and has x-intercepts -8 and 72

Mathematics
1 answer:
bixtya [17]2 years ago
3 0

Step-by-step explanation:

as x intercepts are -8 and 72 we realize that f(x)=a(x+8)(x-72)

we know that f(62)=-490 so a= -0.7

so f(x)= -0.7(x+8)(x-72)

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Answer:

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Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

A = \int_{-\infty}^1 \frac{5}{(x-2)^2}

For this case we can use the following substitution u = x-2 and we have dx = du

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A = -\frac{5}{x-2} \Big|_{-\infty}^1

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So then the integral converges and the area below the curve and the x axis would be 5.

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