All categories

2 years ago

What is your height in centimeters? what is your weight in Newton's

Physics

2 answers:

Gala2k [10]2 years ago

6 0

157.48 centimeters

1201.01984 newtons

goldfiish [28.3K]2 years ago

4 0

My height is 178 centimeters.
My weight is 700N.

You might be interested in

How much work is required to compress 5.05 mol of air at 19.5°C and 1.00 atm to one-eleventh of the original volume by an isothe

Rus_ich [418]

Explanation:

(a) For an isothermal process, work done is represented as follows.

W = $-nRT ln(\frac{V_{2}}{V_{1}})$

Putting the given values into the above formula as follows.

W = $-nRT ln(\frac{V_{2}}{V_{1}})$

= $- 5.05 mol \times 8.314 J/mol K \times (19.5 + 273) K \times ln (\frac{\frac{V_{1}}{11}}{V_{1}})$

= $-12280.82 \times ln (0.09)$

= $-12280.82 \times -2.41$

= 29596.78 J

or, = 29.596 kJ (as 1 kJ = 1000 J)

Therefore, the required work is 29.596 kJ.

(b) For an adiabatic process, work done is as follows.

W = $\frac{P_{1}V^{\gamma}_{1}(V^{1-\gamma}_{2} - V(1-\gamma)_{1})}{(1 - \gamma)}$

= $\frac{-nRT_{1}(11^{\gamma - 1} - 1)}{1 - \gamma}$

= $\frac{-5.05 \times 8.314 J/mol K \times 292.5 (11^{1.4 - 1} - 1)}{1 - 1.4}$

= 49.41 kJ

Therefore, work required to produce the same compression in an adiabatic process is 49.41 kJ.

(c) We know that for an isothermal process,

$P_{1}V_{1} = P_{2}V_{2}$

or, $P_{2} = \frac{P_{1}V_{1}}{V_{2}}$

= $1 atm (\frac{V_{1}}{\frac{V_{1}}{11}})$

= 11 atm

Hence, the required pressure is 11 atm.

(d) For adiabatic process,

$P_{1}V^{\gamma}_{1} = P_{2}V^{\gamma}_{2}$

or, $P_{2} = P_{1} (\frac{V_{1}}{V_{2}})^{1.4}$

= $1 atm (\frac{V_{1}}{\frac{V_{1}}{11}})^{1.4}$

= 28.7 atm

Therefore, required pressure is 28.7 atm.

6 0

3 years ago

An object's velocity can be described by its speed and acceleration.

dezoksy [38]

Hey there!

<span> An object's velocity can be described by its speed and acceleration.

This statement is true

Hope this helps
Have a great day (:
</span>

5 0

3 years ago

Read 2 more answers

Two insulated wires, each 2.50 m long, are taped together to form a two-wire unit that is 2.50 m long. One wire carries a curren

liubo4ka [24]

Answer:

3.46 A

Explanation:

The force (F) exerted on a wire of a particular length (L) carrying current (I) through a magnetic field (B) at an angle (θ) to the magnetic field is given as

F = (B)(I)(L) sin θ

F = 3.13 N

B = 0.360 T

I = ?

L = 2.50 m

θ = 79°

3.13 = (0.360 × I × 2.5 × sin 79°)

0.8835 I = 3.13

I = 3.54 A

But this is the resultant current in this magnetic field.

Since the two wires are conducting current in opposite directions,

Resultant current = 7 - (current in the other wire)

Current in the other wire = 7 - 3.54 = 3.46 A

3 0

2 years ago

Which of the following is an example of static friction?

boyakko [2]

Answer: C) Rubbing sticks together to create a fire.

6 0

3 years ago

Read 2 more answers

If the archerfish spits its water 60. degrees from the horizontal aiming at an insect 2.0 m above the surface of the water, how

MA_775_DIABLO [31]

<span>Using the kinematic equations below, we can calculate the initial velocity required. Angle of projectile = 60 degrees Acceleration due to gravity (Ay) = -10 m/s^2 (negative because downward) Height of projectile (Dy) = 2m Vfy^2=Voy^2 +2*Ay*Dy Vfy = 0 m/s because the vertical velocity slows to zero at the height of its trajection. So... 0 = Voy^2 + 2(-10)(2) 0 = Voy^2 - 40 40 = Voy^2 Sqrt40 = Voy 6.32 m/s = Voy THIS IS NOT THE ANSWER. THIS IS JUST THE INITIAL VELOCITY IN THE Y DIRECTION. Using trigonometry, Tan 60 = Voy/Vox. Tan 60 = 6.32/Vox. Vox*Tan 60 = Vox Vox = 10.95 m/s. Now, using Vox = 10.95 and Voy = 6.32, we can use pythagorean theorem to find the total Vo. A^2 +B^2 = C^2 10.95^2 + 6.32^2 = C^2 Solving for C = 12.64 m/s This is the velocity required to hit the surface. You can also calculate a bunch of other stuff now using the other kinematic equations. V = 12.64 m/s</span>

5 0

3 years ago

Read 2 more answers