Are you looking for the amount after interest gained? If so I believe the answer would be $40.
500 x 0.04 x 2 = 40
Split the shape in to two this is the rectangular side.
15+6=21
21×7=147
147×4=588in
square shape
6+6=12
12×12=144
144×4=576in
then add the answers together
588+576=1164in
1164 is how many more inches greater
Answer:
if it is TSA- 396 or 395.64
if it is CSA- 88 or 87.92
Step-by-step explanation:
r=7
h=2
TSA= 2 pi r(r+h)
=2*22/7*7*9= 396
<em>CSA</em>= 2 pi r h
2*22/7*7*2=88
when you use pi as 3.14 instead of 22/7 you get the answer with the decimal symbol.. in such case the TSA would be 395.64 and CSA would be 87.92
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
Side = 8m
He increases length by 2m and reduces width by 2m
(a.) New dimensions will be -
Length = 10m and Width = 6m
(b.) Area = length x breadth (or width)
here we will use the special product (x+y) (x-y)
length = (x+y) and width = (x-y)
area = (8+2) x (8-2)
8^(2) - 2^(2)
= 60
