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avanturin [10]
2 years ago
15

Can two (or more) types of matter occupy the same space at the same time?

Chemistry
1 answer:
frez [133]2 years ago
8 0

The general properties of matter result from its relationship with mass and space. ... Because it occupies space, all matter has volume and impenetrability, since two objects cannot occupy the same space simultaneously.

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The specific heat of aluminum is 0.897 j/g•°c. which equation would you use to calculate the amount of heat needed to raise the
Varvara68 [4.7K]
<span>c. q = 0.75 g x 0.897 j/g•°c x 22°c</span>
7 0
3 years ago
Negative charge is placed in an eletric
leonid [27]
I would i have think it is either a) east or c) west b/c couldn’t go by it self
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A container of carbon dioxide has a volume of 240 mL at a temperature of 22°C. If the pressure remains constant, what is the vol
astraxan [27]

Answer:

Volume of the CO_{2} gas at 44°C is <u>258 ml.</u>

Explanation

here,

using Charles' law ,

\frac{V}{T} =\frac{v}{t}

where , V= initial volume          v= final volume

             T=initial temperature    t = final temperature

Given - pressure is constant ,

so , putting the values -

V= 240ml

T= 22 + 273K = 295K                      (since converting celsius into kelvin that

                                                         is +273K )

v =?

t = 44+ 273K = 317K

Now , putting the given values in charles' law ,

\frac{240ml}{295K} =\frac{v}{317K}

240ml x317K = v x 295K     (through cross multiplication )

v =\frac{240ml\times317K}{295K}

= 258ml .

thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>

7 0
3 years ago
Check if these are right please, and correct me on any of them:
TiliK225 [7]
I believe those all look correct!

4 0
3 years ago
A bottle of a commercial reagent-grade hydrochloric acid, HCI, has the following
Doss [256]

The volume of concentrated HCl : 2.073 ml

<h3>Further explanation</h3>

Given

37% HCl by mass; density 1.19 g/mL

Required

The volume of concentrated HCl

Solution

Conversion to molarity :

37% x 1.19 g/ml =0.4403 g/ml

g/ml to mol/L :

=0.4403 g/ml x 1000 ml/L : 36.5 g/mol

=12.06 mol/L

or we can use formula :

\tt M=\dfrac{\%\times \rho\times 10}{MM}\\\\M=\dfrac{37\times 1.19\times 10}{36.5}\\\\M=12.06

Dilution formula :

M₁V₁=M₂V₂

12.06 M x V₁ = 0.1 M x 0.25 L

V₁ = 0.0021 L = 2.073 ml

4 0
2 years ago
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