Answer:
Na2O+H2O=2NaOH
Step by step exp.
Given:
Equation Na2O+H2O=NaOH
To find: Balance the equation
Solution:
Taking LHS of the equation
LHS=Na2O+H2O
There is 2 sodium, 2 oxygen,& 2 hydrogen
To balance the equation we have equal number of atom so we multply 2 to the RHS=2NaOH
There fore the equation form is
Na2O+H2O=2NaOH
Kinetic energy if it's based on temperature but potential energy is talking in terms of entropy
The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
<h3>What is Enthalpy of Fusion ?</h3>
The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.
<h3>How to find the change in energy ? </h3>
To find the change in energy use this expression:
q = n ΔH
where
q = Energy change
n = number of moles
ΔH = Molar enthalpy
Number of moles (n) = ![\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
= ![\frac{78.0\ g}{200\ \text{g/mol}}](https://tex.z-dn.net/?f=%5Cfrac%7B78.0%5C%20g%7D%7B200%5C%20%5Ctext%7Bg%2Fmol%7D%7D)
= 0.39 mol
Now put the values in above formula we get
q = n ΔH
= 0.39 mol × 2.29 kJ/mol
= 0.89 kJ
Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
Learn more about the Latent heat of fusion here: brainly.com/question/87248
#SPJ1
Answer:
8 mins and 20 seconds i think
Explanation:
Answer:
0.0566 moles/liter
Explanation:
molarity= moles/liter of solution
molarity=8.1mole/143 liter = 0.0566