A I have a periodic table with me I checked
Answer:the answer is A I think, tell me if I’m wrong
Explanation:
Answer:
AgNO2
Explanation:
The question asks to know which of these two insoluble salts is expected to be more soluble in acidic solution than in pure water.
To answer this question specifically, we need to know if the anions contained in the insoluble salt is a conjugate of a weak acid or that of a weak base.
Generally, the solubility of insoluble salts that contain anions which are conjugates of weak acids increases in the presence of an acidic solution than in water. While, the solubility of insoluble salts that contain anions which are conjugates of strong acids decreases in the presence of an acidic solution.
Having said this, AgNO2 contains NO2 which is the conjugate base of the Trioxonitrate iii acid which is a weak acid. Hence, it is expected to be stronger in acidic solution than in water.
Answer:
34g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H2S + 2AgNO3 —> 2HNO3 + Ag2S
Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.
This is illustrated below:
From the balanced equation above,
We can see that 1 mole of H2S is required to react completely with 2 moles of AgNO3.
Finally, we shall convert 1 mole of H2S to grams. This is shown below:
Number of mole H2S = 1 mole
Molar mass of H2S = (2x1) + 32 = 34g/mol
Mass = number of mole x molar Mass
Mass of H2S = 1 x 34
Mass of H2S = 34g
Therefore, 34g of H2S is needed to react with 2 moles of AgNO3.
Answer: The molecular formula will be 
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C= 13.65 g
Mass of F = 86.35 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of F=
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = 
For F = 
The ratio of C : F= 1: 4
Hence the empirical formula is
The empirical weight of 
= 1(12)+4(19)= 88g.
The molecular weight = 88.01 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=
