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2 years ago

Solve: 8t + 2 = 8 (4) + 2 = ? + 2 What is the (?) / Question mark?

Mathematics

1 answer:

Genrish500 [490]2 years ago

6 0

Answer:

? = 32

Step-by-step explanation:

Because 8 times 4=32 plus 2 = 34 and therefore t=4 8 times 4 again plus 2 = 34 so 32 plus 2 =34

Plz give brainliest

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

Y=x2 x=-3 -2 -1 0 1 2 3 y=

brilliants [131]

Answer:

see below

Step-by-step explanation:

Y=x^2

x=-3 -2 -1 0 1 2 3

y=(-3)^2 (-2)^2 (-1)^2 0^2 1^2 2^2 3^2

9 4 1 0 1 4 9

7 0

3 years ago

It’s geometry I have a triangle left side is just a c right side is 80cm and the bottom is 18cm but there’s a right angle in the

Monica [59]

Answer:

i think its 10cm

Step-by-step explanation: brainlyest plz :)

90+80=170

180-170=10

7 0

3 years ago

Evaluate AB for A = 5, B =-2, C = 4 and D = -6. 5/12 -5/12 -3/2 3/2

Nezavi [6.7K]

Answer:

AB = -10

Im confused is this what you wanted?

5 0

3 years ago

Find x so that l || m. state the converse used.

kenny6666 [7]

Answer:

$x = 12$

Converse: Alternate Interior Angles Converse

Step-by-step explanation:

By the Alternate Interior Angles Converse, if $(14x - 23) = (9x + 37)$ , then l || m.

Use the equation to solve for x as follows:

$14x - 23 = 9x + 37$

Subtract 9x from each side

$14x - 23 - 9x = 9x + 37 - 9x$

$5x - 23 = 37$

Add 23 to both sides

$5x - 23 + 23 = 37 + 23$

$5x = 60$

Divide both sides by 5

$\frac{5x}{5} = \frac{60}{5}$

$x = 12$

4 0

3 years ago