The cost of book has to be less than or equal to 26.39.
The amount of money Elena can buy has to be less than or equal to $30. Thus, the inequality sign to be used is the less than or equal to sign.
(1 + tax)cost of books + cost of bus fare ≤ value of the gift
1.08c + 1.5 ≤ 30
In order to determine the maximum cost of books, take the following steps:
Combine similar terms
1.08c ≤ 30 - 1.5
Add similar terms together
1.08c ≤ 28.50
Divide both sides of the equation by 1.08
c ≤ 28.50 / 1.08
c ≤ 26.39
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600,00,000 40,000,000 3,000,000 60 2 is this what our asking
Assuming 5a3 equals 5a^3, and the same for everything else, you would plug in 4 for a, so 5(4)^3 - 2(4)^2 + 4 - 45, which equals 247.
Answer:
z=30
Step-by-step explanation:
40-10=30
10+10+?=30
30-10-10=10
I'm sorry cuz I don't know how to explain it
Answer:
- It is the last graph: solid line, shaded area over the line x = 2 - x/2
Explanation:
1) <u>Set the algebraigic expression that represents the combinations of sofa and pillow orders:</u>
- Number of sofas: x (given)
- Number of pillows: 2y (given, since they come in pairs)
- Number of items = number of sofas + number of pillows = x + 2y
- Minimum of 4 items in each order (given) ⇒ x + 2y ≥ 4
<u>2) Predict the graph of the inequality x + 2y ≥ 4</u>
- The border line is the equation x + 2y = 4
- You can choose two points to draw a line
- Choose the axis-intercepst:
x = 0 ⇒ 2y = 4 ⇒ y =4/2 ⇒ y = 2 ⇒ point (0,2)
y = 0 ⇒ x = 4 ⇒ point (4,0)
Then the lines goes through (0,2) and (4,0) ... [the four graphs meet this]
- The shading area is above the line because when you solve for y you get y ≥ 2 - x/2, and the line is included because the "equal to" part of the symbol (≥ means greater than or equal to).
- To state that the line is included the graph uses a continous line instead of a dotted one.
<u>3) Conclusion:</u>
That means that the correct graph is the last one: solid line, shaded area over the line y = 2 - x/2.
Note: a more detailed graph would include the fact that the items cannot be negative, i.e. x ≥ 0 and y ≥ 0, which would result in that the shaded area would be on the first quadrant.
