M(KNO₃)=101.1 g/mol
M(CO(NH₂)₂)=60.1 g/mol
m(N)=M(N)m(KNO₃)/M(KNO₃)
m(N)=2M(N)m(CO(NH₂)₂)/M(CO(NH₂)₂)
2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃)
m(CO(NH₂)₂)=M(CO(NH₂)₂)m(KNO₃)/(2M(KNO₃))
m(CO(NH₂)₂)=60.1*101.1/(2*101.1)=30.05 g
The reaction between hydrogen and oxygen to form water is given as:
The balanced reaction is:
According to the balanced reaction,
4 g of hydrogen (
) reacts with 32 g of oxygen (
).
So, oxygen reacted with 29.4 g of hydrogen is:
Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.
Answer:
Formic acid H. COOH
Acetic acid CH3.COOH
Propionic acid CH3 . CH1 . COOH
Butyric acid CH3 . CH1 . CH1 . COOH
Explanation:
The answer is (2). To calculate the density, you need to divide the mass with volume. When doing division, the significant figures of result is the minimal of the numbers using before. So the answer is 2.
Because the temperature and pressure are not below 100c or above 100000KPa
