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Makovka662 [10]
4 years ago
8

Calculate the percent yield if 52.9 g of ethanol reacts to produce 26.7 g of ether.

Chemistry
1 answer:
blagie [28]4 years ago
6 0

Answer:

The % yield is 62.7 %

Explanation:

<u>Step 1:</u> the balanced equation

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

<u>Step 2:</u> Data given

mass of ethanol = 52.9 grams

molar mass of ethanol = 46.07 g/mol

mass of ether = 26.7 grams

Molar mass of ether = 74.12 g/mol

<u>Step 3:</u> Calculate moles of ethanol

Number of moles = Mass / molar mass

Moles of ethanol = 52.9 grams / 46.07 g/mol

Moles of ethanol = 1.15 moles

<u>Step 4: </u>Calculate moles of ether

For 2 moles of ethanol consumed, we have 1 mole of ether produced

For 1.15 moles of ethanol consumed, we have 1.15/2 = 0.575 moles of ether produced

<u>Step 5:</u> Calculate mass of ether

Mass = moles * Molar mass

Mass ether = 0.575 moles * 74.12 g/mol = 42.62 grams = theoretical yield

<u>Step 6:</u> Calculate % yield

% yield = (26.7 / 42.62) * 100 = 62.7%

The % yield is 62.7 %

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