1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesantik [10]
3 years ago
9

Jane plans to fly from Binghamton, New York, to Springfield, Massachusetts, about 280 km due east of Binghamton. She heads due e

ast at 280 km/h for one hour but finds herself at Keene, which is 294 km from Binghamton in a direction 17.8 degrees north of due east. What was the wind velocity
Physics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

You might be interested in
The centripetal force acting on the space shuttle
KIM [24]
The centripetal force acting on the space shuttle as it orbits Earth is equal to the shuttles momentum
4 0
4 years ago
A box is being dragged with a horizontal force of 65 N for 12 meters. If there is a force of friction acting on it
asambeis [7]

Answer:

A. 780 J

B. 120 J

C. 660 J

Explanation:

From the question given above the following data were obtained:

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

A. Determination of the work done by the dragging force.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Workdone (Wd) by dragging force =?

Wd = Fₔ × s

Wd = 65 × 12

Wd = 780 J

Therefore, the work done by the dragging force is 780 J

B. Determination of the work done by friction.

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Workdone (Wd) by friction =?

Wd = Fբ × s

Wd = 10 × 12

Wd = 120 J

Therefore, the work done by friction is 120 J

C. Determination of the net work done on the box.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Net work done (Wd) =?

Next, we shall determine the net force acting on the box. This can be obtained as follow:

Dragging force (Fₔ) = 65 N

Force of friction (Fբ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₔ – Fբ

Fₙ = 65 – 10

Fₙ = 55 N

Thus, the net force acting on the box is 55 N

Finally, we shall determine the net work done on the box as follow:

Distance (s) = 12 m

Net force (Fₙ) = 55 N

Net work done (Wd) =?

Wd = Fₙ × s

Wd = 55 × 12

Wd = 660 J

Therefore, the net work done on the box is 660 J

4 0
3 years ago
A car driver traveling at a speed of 108km per hour ,sees a traffic light and stopped after travelling for 20seconds .Find the a
navik [9.2K]

Answer:

– 2.5 m/s²

Explanation:

We have,

• Initial velocity, u = 180 km/h = 50 m/s

• Final velocity, v = 0 m/s (it stops)

• Time taken, t = 20 seconds

We have to find acceleration, a.

\longrightarrow a = (v ― u)/t

\longrightarrow a = (0 – 50)/20 m/s²

\longrightarrow a = –50/20 m/s²

\longrightarrow a = – 5/2 m/s²

\longrightarrow a = – 2.5 m/s² (Velocity is decreasing) [Answer]

6 0
3 years ago
the hydrometer with the density of liquid to be 800 kg metre per square is the volume of the submerged part of the hydrometer is
julia-pushkina [17]

Answer:

Mass = 0.04 Kg

Explanation:

Given the following data;

Density = 800 kg/m³

Volume = 5 * 10^{-5} m³

To find the mass of the object;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

Density = \frac {mass}{volume}

Making mass the subject of formula, we have;

Mass = density * volume

Substituting the values into the formula, we have;

Mass = 800 * 5 * 10^{-5}

Mass = 0.04 Kg

8 0
3 years ago
A man on a bicycle of total mass of 10kg has a Velocity of 2 ms.' He Paddles faster for 5 seconds and the velocity Increase to i
sesenic [268]

Answer:

the value of force, F=4.0N

Explanation:

Firstly, recall velocity-time equation

  • v=u+at
  • (4)=(2)+a(5)
  • a=0.4m/s²

Secondly, recall the Newton's 2nd Law

  • <em>F</em><em>=</em><em>ma</em>
  • <em>F</em><em>=</em><em>(</em><em>1</em><em>0</em><em>)</em><em>(</em><em>0</em><em>.</em><em>4</em><em>)</em>
  • <em>F</em><em>=</em><em>4</em><em>.</em><em>0</em><em>N</em>
7 0
2 years ago
Other questions:
  • A cheetah is walking at 5.0m/s when it sees a zebra 35m away. What acceleration would be required for the cheetah to reach 25.0
    9·1 answer
  • A puppy finds a rawhide bone and begins to pull it with a force, Ft. The free-body diagram is shown. Which describes what happen
    11·2 answers
  • What is the trademark of the Harlem Globetrotters?
    13·1 answer
  • A positively charged particle initially at rest on the ground accelerates upward to 160 m/s in 2.10 s. The particle has a charge
    6·2 answers
  • Why do antoms move at different speeds depending pn weather they are in liqids or solids?
    9·1 answer
  • Elements in the family often have a similar
    6·2 answers
  • Kinds of solar power stations
    13·1 answer
  • Sl unit of upthrust and SI unit of pressure​
    5·1 answer
  • What are vernier callipers?​
    6·2 answers
  • Help Me Please<br>8th grade science, one question ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!