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musickatia [10]
3 years ago
8

Use the circuit diagram to determine the voltage drop across the 8 Ω resistor.

Physics
2 answers:
Rainbow [258]3 years ago
8 0
First we need to find the current flowing in the circuit. The three resistors are in series, so the equivalent resistance of the circuit is the sum of the three resistances:
R_{eq} = R_1 + R_2 + R_3 = 10.0 \Omega + 8.0 \Omega +6.0 \Omega = 24.0 \Omega

Then we can apply Ohm's law to the whole circuit, to find the current flowing:
I= \frac{V}{R_{eq}}= \frac{12 V}{24.0 \Omega}=0.5 A

And now we can apply Ohm's law to the resistor of 8.0 \Omega to find the voltage drop across it:
V_{8\Omega} =IR=(0.5 A)(8.0 \Omega)=4 V
LenaWriter [7]3 years ago
3 0

Answer:

4 V

Explanation:

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