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Natalka [10]
2 years ago
14

A car accelerates from rest at a rate of 6.50 m/s2. Determine thevelocity of the car at t = 4.00 s.

Physics
1 answer:
aksik [14]2 years ago
3 0

Answer:

1.62 m/s2

Explanation:

6.50 divided by 4

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Answer:

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Explanation:

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= [Zm_p + (A - Z)m_n - N]c^2\\\\=[(1) (1.007825u) + (2 - 1 ) ( 1.008665 u) - 2.014102 u]c^2\\\\= (0.002388u)c^2\\\\= (.002388) (931.5 MeV)\\\\=2.22 MeV

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As 1 MeV = (1 u) c^2

hence, the binding energy is 2 MeV

Therefore the correct option is c.

We simply applied the above formula so that the correct binding energy could come

And, the same is to be considered

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12345 [234]

Answer:

Explanation:

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