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ser-zykov [4K]
2 years ago
8

Which compounds were classified as organic compounds according to the early chemists​

Chemistry
1 answer:
Alona [7]2 years ago
5 0

Answer:

Organic compound, any of a large class of chemical compounds in which one or more atoms of carbon are covalently linked to atoms of other elements, most commonly hydrogen, oxygen, or nitrogen.

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13. When iron nad is put in to a beaker containing copper sulphate solution.
svetlana [45]

Answer:

A simple displacement reaction occurs when an iron nail is immersed to a beaker containing copper sulphate solution.

a)

Iron is more reactive than copper. As a result a displacement reaction will take place. The ferrous or Fe (II) irons will move to the solution. The copper ions (Cu II) will get deposited on the nail. This will cause the colour to change from blue to green.

b)

The equation can be written as:

Fe (s) + CuSO4 (aq) -> FeSO4 (aq) + Cu (s)

c)

A chemical change can be described as a change that causes a substance to change to another form. Hence, this reaction is a chemical change.

4 0
3 years ago
How many molecules of hypothetical substance b are produced when 29.9g of hypothetical substance a reacts? the molar mass of sub
Andrej [43]
<span>1.15x10^24 molecules of hypothetical substance b Making the assumption that each molecule in hypothetical substance a reacts to produce a single molecule of hypothetical substance b, then the number of molecules of substance b will be the number of moles of substance a multiplied by avogadro's number. So Moles hypothetical substance a = 29.9 g / 15.7 g/mol = 1.904458599 moles This means that we should also have 1.904458599 moles of hypothetical substance b. And to get the number of atoms, multiply by 6.0221409x10^23, so: 1.904458599 * 6.0221409x10^23 = 1.146892x10^24 molecules. Rounding to 3 significant figures gives 1.15x10^24</span>
5 0
3 years ago
Analyzing and interpreting data
Lana71 [14]
It’s blurry i can’t see
4 0
3 years ago
How many atoms are in 4NH3
aivan3 [116]

I think it 2.25 or somethingg

7 0
3 years ago
Read 2 more answers
Can someone how to do these problems!!
Novosadov [1.4K]
You can use the follwing equations.
pH=14-pOH
pOH=-log[OH⁻]

a)  pOH=-log10⁻¹²
     pOH=12
     pH=14-12
     pH=2

You can also use these equations:
[H⁺]=K(w)/[OH⁻]    (K(w)=1.01×10⁻¹⁴)
pH=-log[H⁺]

b) [H⁺]=(1.01×10⁻¹⁴)/10⁻²M
    [H⁺]=1.01×10⁻¹²M²
    pH=-log(1.01×10⁻¹²)
    pH=12

You can use either method.  It does not really matter.
I hope this helps.  Let me know if anything is unclear and when you do the calculations for c you should get pH=7.
3 0
3 years ago
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