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Goshia [24]
2 years ago
5

Suppose you are performing a titration. At the beginning of the titration, you read the titrant volume as 2.51 mL. After running

the titration and reaching the endpoint, you read the titrant volume as 29.95 mL. What volume, in mL, of titrant was required for the titration
Chemistry
1 answer:
antoniya [11.8K]2 years ago
3 0

The volume of titrant required for the titration would be 27.44 mL

From the illustration, the initial titrant volume was 2.51 mL. This figure represents the initial reading on the burette.

In the same vein, the final volume of the titrant was 29.95 mL. This figure represents the final reading on the burette.

In order to get the volume of titrant used:

Volume of titrant used = final volume - initial volume

                             = 29.95 - 2.51

                                = 27.44 mL

More on the volume of titrant used in titrations can be found here: brainly.com/question/4250180

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When 3.00 g of sulfur are combined with 3.00 g of oxygen, 6.00 g of sulfur dioxide (SO2) are formed. What mass of oxygen would b
bazaltina [42]
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

6 g S * 1 mol/32.06 g S = 0.187 mol S
Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂
4 0
3 years ago
Zinc is used as a coating for steel to protect the steel from environmental corrosion. If a piece of steel is submerged in an el
sweet [91]

Answer:

A) 3.17 g of Zn

Explanation:

Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.

Zn⁺²(aq) + 2e⁻ → Zn(s)

We can establish the following relations:

  • 1 min = 60 s
  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
  • When 2 moles of electrons circulate, 1 mole of Zn is deposited.
  • The molar mass of Zn is 65.38 g/mol

The mass of Zn deposited under these conditions is:

24min \times \frac{60s}{1min} \times \frac{6.5C}{s} \times \frac{1mol\ e^{-} }{96,468C} \times \frac{1molZn}{2mol\ e^{-}}  \times \frac{65.38g}{1molZn} = 3.17 g

3 0
3 years ago
What is the percent by mass of carbon in c10 h14 n2?
bonufazy [111]
Add all weighs together
calculate carbons weigh
(carb weigh/total)×100
3 0
3 years ago
Whats the name?!?!?!??!?!?!?!?!?!?!!?!?!?!??!?!?!?!
SIZIF [17.4K]
Hydrogen i suppose is the right one
7 0
3 years ago
Volume is an extensive physical property because it is dependent on the size of the sample.
BaLLatris [955]
Hi,

The statement is true, as the volume of a sample depends on its size.

I hope this helps. If I was not clear enough or if you’d like further explanation please let me know. Also, English is not my first language, so I’m sorry for any mistakes.
7 0
3 years ago
Read 2 more answers
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