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AleksandrR [38]

1 year ago

13

If a powerful gravitational wave passed through you body, moving from your back to your chest, what would happen to your body

1 answer:

Rama09 [41]1 year ago

8 0

Answer:

If a powerful gravitational wave passed through you body, moving from your back to your chest, what would happen to your body? Your width and height would both oscillate in such a way that you would get taller as you got narrower and shorter as you got wider.

Explanation:

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When an airplane flies from Dallas - Ft. Worth International airport to Los Angeles International airport, the time in the air i

Elanso [62]

Answer:

7.99 or 8 depends where you round.

Explanation:

Distance divided by time so 1246/156=7.98717948718

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2 years ago

A microscope that uses light and more than one lens

gulaghasi [49]

A compound optical microscope or just a optical microscope is a microscope that uses light and has more than one lens.

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2 years ago

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A boy drags a box of toys.It experiences a frictional force of 10N .calculate acceleration of the system

hodyreva [135]

Answer:

20 N

Explanation:

i believe that is right

7 0

2 years ago

A rocket in deep space has an empty mass of 150 kg and exhausts the hot gases of burned fuel at 2500 m/s. It is loaded with 600

3241004551 [841]

Answer:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

Explanation:

The speed of the rocket is given the Tsiolkovsky's differential equation, whose solution is:

$v (t) = v_{o} - v_{ex}\cdot \ln \frac{m}{m_{o}}$

Where:

$v_{o}$ - Initial speed of the rocket, in m/s.

$v_{ex}$ - Exhaust gas speed, in m/s.

$m_{o}$ - Initial total mass of the rocket, in kg.

$m$ - Current total mass of the rocket, in kg.

Let assume that fuel is burned linearly. So that,

$m(t) = m_{o} + r\cdot t$

The initial total mass of the rocket is:

$m_{o} = 750\,kg$

The fuel consumption rate is:

$r = -\frac{600\,kg}{30\,s}$

$r = -20\,\frac{kg}{s}$

The function for the current total mass of the rocket is:

$m(t) = 750\,kg - (20\,\frac{kg}{s} )\cdot t$

The speed function of the rocket is:

$v(t) = - 2500\,\frac{m}{s}\cdot \ln \frac{750\,kg -(20\,\frac{kg}{s} )\cdot t}{750\,kg}$

The speed of the rocket at given instants are:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

7 0

2 years ago

PLEASE HELP it takes tsooo long! lol ima fail! please help! thanks!

jenyasd209 [6]

Answer:

Tidal Turbins

Explanation:

8 0

2 years ago