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DENIUS [597]
3 years ago
7

In which situations is gravitational potential energy present? Check all that apply. A person walks up a flight of stairs. A per

son runs across a room. Wind blows against a steel table anchored to the ground. Wind lifts a balloon into the air. A weightlifter holds a barbell on the ground. A weightlifter holds a barbell straight overhead
Physics
2 answers:
vova2212 [387]3 years ago
8 0

Answer:  

A person walks up a flight of stairs.

Wind lifts a balloon into the air.

A weightlifter holds a barbell straight overhead

Explanation:

<u>Gravitational potential energy is possessed by a body due to virtue of its position (height). </u>

A body placed some height above the ground possesses gravitational potential energy which is equal to the work done to lift it.

Thus, a person who walks up a flight of stairs, a weightlifter holding barbell straight overhead and wind lifting balloon into the air have gravitational potential energy.

Dimas [21]3 years ago
7 0
 The first, fourth and sixth options. A person walks up a flight of stairs, wind lifts a balloon into the air, and a weightlifter holds a barbell straight overhead.
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Answer:

0.75 g/cm^3

Explanation:

The formula for density:

\rho = \frac{m}{V}

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So, we can substitute values for m and V:

\rho = \frac{277}{370}\approx0.75

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2 years ago
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Turn the ignition switch to start and release the key immediately or you could destroy the______________.
vredina [299]

Starter

Explanation:

Turn the ignition switch to start and release the key immediately or you could destroy the starter.

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3 years ago
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Allisa [31]
The energy absorbed by photon is 1.24 eV.
This is the perfect answer.
8 0
2 years ago
4) A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
VMariaS [17]

Answer:

(a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

Explanation:

Given that,

A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.

Suppose, the distance between 40 yard line and 25 yard line is 20 yard.

(a). We need to calculate their speed during that run

Using formula of speed

v=\dfrac{d}{t}

Where. d = distance

t = time

Put the value into the formula

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(b). We need to calculate their velocity

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v=\dfrac{\Delta d}{\Delta t}

Put the value into the formula

v=\dfrac{22.86-36.58}{2}

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Negative sign shows the direction of motion.

(c). If they kept running at that velocity for another 1.3 seconds,

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Using formula of position

d=vt

Put the value into the formula

d=6.86\times1.3

d=8.91\ m

Hence, (a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

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