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DENIUS [597]
3 years ago
7

In which situations is gravitational potential energy present? Check all that apply. A person walks up a flight of stairs. A per

son runs across a room. Wind blows against a steel table anchored to the ground. Wind lifts a balloon into the air. A weightlifter holds a barbell on the ground. A weightlifter holds a barbell straight overhead
Physics
2 answers:
vova2212 [387]3 years ago
8 0

Answer:  

A person walks up a flight of stairs.

Wind lifts a balloon into the air.

A weightlifter holds a barbell straight overhead

Explanation:

<u>Gravitational potential energy is possessed by a body due to virtue of its position (height). </u>

A body placed some height above the ground possesses gravitational potential energy which is equal to the work done to lift it.

Thus, a person who walks up a flight of stairs, a weightlifter holding barbell straight overhead and wind lifting balloon into the air have gravitational potential energy.

Dimas [21]3 years ago
7 0
 The first, fourth and sixth options. A person walks up a flight of stairs, wind lifts a balloon into the air, and a weightlifter holds a barbell straight overhead.
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Two carts, one twice as heavy as the other, are at rest on a horizontal track. A person pushes each cart for 8 s. Ignoring frict
GalinKa [24]

Answer:

The correct option is: B that is 1/2 K

Explanation:

Given:

Two carts of different masses, same force were applied for same duration of time.

Mass of the lighter cart = m

Mass of the heavier cart = 2m

We have to find the relationship between their kinetic energy:

Let the KE of cart having mass m be "K".

and KE of cart having mass m be "K1".

As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.

Numerical analysis.

⇒ KE =  \frac{mv^2}{2}

⇒ KE =  \frac{mv^2}{2}\times \frac{m}{m}

⇒ KE =  \frac{m^2v^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(mv)^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(\triangle p)^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(\triangle p)^2}{2m}=\frac{(F\times t)^2}{2m}

Now,

Kinetic energies and their ratios in terms of momentum or impulse.

KE (K) of mass m.

⇒ K=\frac{(F\times t)^2}{2m}           ...equation (i)

KE (K1) of mass 2m.

⇒ K_1=\frac{(F\times t)^2}{2\times 2m}

⇒ K_1=\frac{(F\times t)^2}{4m}         ...equation (ii)

Lets divide K1 and K to find the relationship between the two carts's KE.

⇒ \frac{K_1}{K} =\frac{(F\times t)^2}{4m} \times \frac{2m}{(F\times t)^2}

⇒ \frac{K_1}{K} =\frac{2m}{4m}

⇒ \frac{K_1}{K} =\frac{2}{4}

⇒ \frac{K_1}{K} =\frac{1}{2}

⇒ K_1=\frac{K}{2}

⇒ K_1=\frac{1}{2}K

The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.

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3 years ago
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Vilka [71]
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3 years ago
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The Indianapolis Motor Speedway has four banked curves, each of which forms a quarter of a circle. Suppose a race car speeds alo
boyakko [2]

Answer:

r =  255.68 m

Explanation:

When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:

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v = tangential speed = 75 m/s

r = radius of curve = ?

Therefore,

22 m/s² = (75 m/s)²/r

r = (75 m/s)²/(22 m/s²)

<u>r =  255.68 m</u>

4 0
3 years ago
Fluorine (F) has nine protons and ten neutrons. The atomic mass of fluorine is _____.
wel
The atomic mass is roughly equal to the sum of protons and neutrons of an atom. 
9  protons + 10 neutrons = 19
Atomic mass of Flourine is 19. 
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Aluminum has 3 valence electrons.
<span>You can figure out the valence electrons by looking at its group number. Aluminum is in group 3, so it has 3 valence electrons. </span>
6 0
3 years ago
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