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valentinak56 [21]
3 years ago
6

Key difference of the celsius scale and kevin scale

Physics
1 answer:
mixer [17]3 years ago
6 0

Their 'degrees' are the same size.  The difference between the Celsius
and Kelvin scales is their zero-point.  Zero Kelvin is the absolute zero of
nature and Physics.  Zero Celsius is the melting/freezing point of water,
273.15 higher than absolute zero.

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The x and y components of vector S are -30.0 m and +40.0 m, respectively. Find the magnitude of S and the angle between the dire
34kurt

Answer:

The given vector can be represented in unit vector as

\overrightarrow{w}=-30\widehat{i}+40\widehat{j}

The magnitude of any vector \overrightarrow{r}=u\widehat{i}+v\widehat{j} is given by

|w|=\sqrt{u^{2}+v^{2}}

Applying values we get

|w|=\sqrt{-30^{2}+40^{2}}\\\\|r|=50

We know that positive x axis in vertorial form is represented as

\overrightarrow{r}=\widehat{i}

taking dot product of both the vector's we get

\overrightarrow{r}.\overrightarrow{w}=|r||w|cos(\theta )\\\\\therefore cos(\theta )=\frac{(-30\widehat{i}+40\widehat{j}).\widehat{i}}{50}\\\\\therefore \theta =cos^{-1}(\frac{-30}{50})=126.86^{o}

5 0
3 years ago
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The free body diagram represents Silly Sally hanging from a trapeze bar. Sally weighs 660 Newtons. What is the force in each of
MrRissso [65]

the force in each of the chains holding the trapeze bar is D. 330 N

Her weight has to be divided evenly so, divide 660/2= 330 N

5 0
3 years ago
A grandfather clock is controlled by a swinging brass pendulum that is 1.2 m long at a temperature of 27°C. (a) What is the leng
stealth61 [152]

Answer:

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

Explanation:

Given;

Initial length L1 = 1.2m

Initial temperature T1 = 27°C

Final temperature T2 = 0.0°C

Linear expansion coefficient of brass x = 1.9 × 10^-5 /°C

The change i length ∆L;

∆L = L2 - L1

L2 = L1 + ∆L ...........1

∆L = xL1(∆T)

∆L = xL1(T2 - T1) ......2

Substituting the given values into equation 2;

∆L = 1.9 × 10^-5 /°C × 1.2m × (0 - 27)

∆L = 1.9 × 10^-5 /°C × 1.2m × (- 27)

∆L = -6.156 × 10^-4 m

From equation 1;

L2 = L1 + ∆L

Substituting the values;

L2 = 1.2 m + (- 6.156 × 10^-4 m)

L2 = 1.2 m - 6.156 × 10^-4 m

L2 = 1.1993844 m

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

3 0
3 years ago
Juan rides his horse with a constant<br> speed of 18 km/h. How far can he travel<br> in 1/2 hour?
Brut [27]

Answer:

He traveled 9km

Explanation:

To do this problem you need to use the equation which is Speed= distance/time and this problem gives you the speed which is 18 km/h and it gives you the time 1/2 hour so you write the equation 18= d/ 1/2 which his distance is 9km

3 0
3 years ago
What type of heat transfer is boiling water??
beks73 [17]
Heat can be transferred from one place to another by three methods:

conduction in solids,

convection of fluids (liquids or gases),

radiation through anything that will allow radiation to pass.
6 0
4 years ago
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