Question

The reaction is: Fe2O3 (s) + 2Al (s) → 2Fe (l) + Al2O3 (s)

Answer 1

There are 4.8 moles of Al2O3 produced when 2.4 mol of  Fe2O3 reacts with iron.

a)The equation of the reaction is;  Fe2O3 (s) + 2Al (s) → 2Fe (l) + Al2O3 (s)

From the reaction equation;

2 moles of Al produces 1 moles of Al2O3

x moles of Al produces 2.4 moles of Al2O3

x = 2 moles × 2.4 moles/1 moles

x = 4.8 moles

b) 1 mole of Fe2O3  produces 1 moles of  Al2O3

4.5 moles of Fe2O3  produces 4.5 moles of Al2O3

c) Number of moles in 3.6 g of Al = 3.6 g/27 g/mol = 0.133 moles

If 2 moles of Al yields 1 mole of Al2O3

0.133 moles Al yields 0.133 moles × 1 mole/ 2 moles

= 0.0665 moles

Mass of Al2O3 = 0.0665 moles × 102g/mol

= 6.8 g

d) Number of moles of iron =  3.6 g/56 g/mol = 0.064 moles

From the reaction equation;

1 mole of Al2O3 is produced when 2 moles of iron is produced

x moles of Al2O3 is produced when 0.064 moles is produced

x = 1 mole × 0.064 moles/ 2 moles

x = 0.032 moles

Mass of Al2O3 produced =  0.032 moles ×  102g/mol

= 3.3 g

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