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S_A_V [24]
3 years ago
8

Please answer me ASAP

Chemistry
1 answer:
leva [86]3 years ago
7 0

Answer:

c.filtration is the answer

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A pupil adds 5 cm of 12 mol.dm sulphuric acids to make a 250 cmº solution. Calculate the
klemol [59]

Answer:

0.500 mol/dm³

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (mol/dm³)

Cb = concentration of base (mol/dm³)

Va = volume of acid (cm³)

Vb = volume of base (cm³)

In accordance to the information provided in this question is;

Va = 5cm³

Vb = 250 cm³

Ca = 12 mol/dm³

Cb = ?

Using CaVa = CbVb

12 × 5 = Cb × 250

60 = 120Cb

Cb = 60/120

Cb = 0.500 mol/dm³

8 0
3 years ago
Ethanol had a boiling point of 78.4°C. Propane has a boiling point of -42°C. Suggest why.​
Gwar [14]

Answer:

Chemical compounds all have different melting points.

Explanation:

chemical compounds all have different freezing and boiling points. Different chemical compounds means they will have different chemical structures.

7 0
3 years ago
I'm not 100% sure of the answer. Explanations are highly appreciated.
PolarNik [594]

Answer:

The correct answer is

B.

\Delta H=2(1072)+498 -4(799)

Explanation:

Enthalpy of reaction :

It is the amount of energy released/absorbed when one mole of the substance is formed from the reactant at a constant pressure.

The enthalpy of a reaction can be calculated using :

\Delta H=\Delta H_{reactants}-\Delta H_{products}

2CO+O_{2}\rightarrow 2CO_{2}

\Delta H_{reactants}=2(C\equiv O)+O=O

\Delta H_{reactants}=2(1072)+498

H_{products}=2(2\times C=O)

H_{products}=4\times 799

\Delta H=\Delta H_{reactants}-\Delta H_{products}

\Delta H=2(1072)+498 -4(799)

units = \frac{kJ}{mole}

Please note that :

The carbon monoxide , CO should be taken as C triple bond O. Not C=O .

So , the bond energy =1072 is used

\Delta H=2(1072)+498 -4(799)

8 0
3 years ago
Please I need this help me​
BaLLatris [955]

Answer:

first of all is that really chemistry

3 0
3 years ago
For which of the following equilibria does `"K"_("eq") = ["O"_2]`? A. O2(l) O2(g) B. 2O3(g) 3O2(g) C. 2H2O(l) 2H2(g) + O2(g) D.
Feliz [49]

For plato users

the answer is a. O2(l) O2(g)

hope this helps!

8 0
3 years ago
Read 2 more answers
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