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Softa [21]
3 years ago
7

What is the mole fraction of a solute in a 2.2 molal solution in which naphthalene (C10H8) is the solvent?

Chemistry
1 answer:
vesna_86 [32]3 years ago
4 0

The mole fraction of the 2.2 molal solution whose solvent is naphthalene is 0.28.

Using the relation;

molality = mole fraction × 1000/MA

Where MA = molar mass of the solvent

We know from the question that the molaity of the solution is 2.2 molal

Making the mole fraction the subject of the formula;

mole fraction = molality × MA/1000

MA = 128 g/mol

mole fraction = 2.2 × 128/1000

Mole fraction = 0.28

Learn more: brainly.com/question/2510654

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Which element is similar to the properties bromine?
Ainat [17]

Answer: Fluorine

Explanation: It belongs in the same group as Bromine

8 0
3 years ago
What is the weight of a 90kg man standing on the moon, where gmoon = 1.64 m/s2?
Doss [256]

Answer:

The weigth of a 90kg man standing on the moon is <u><em>147.6 N (option C)</em></u>

Explanation:

Weight is called the action exerted by the force of gravity on the body.

The mass (amount of matter that a body contains) of an object will always be the same, regardless of where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The formula that allows you to calculate the weight of any body is:

W = m*g

where:

  • W = weight measured in N.
  • m = mass measured in kg.
  • g = acceleration of gravity measured in m/s². The acceleration of gravity g is the same for all objects that fall due to gravitational attraction, whatever their size or composition. For example, as an approximate value on Earth, g = 9.8 m/s².

In this case,  the mass m has a value of 90 kg and the gravity g has a value of 1.64 m/s², which is the value of the acceleration of gravity of the moon. Then:

W=90 kg* 1.64 m/s²

<u><em>W= 147.6 N</em></u>

Finally, <u><em>the weigth of a 90kg man standing on the moon is 147.6 N (option C)</em></u>

3 0
3 years ago
PLEASE HELP ME ASAP!!!!!!!!!
snow_lady [41]

Answer:

the answer is c 8.91g/cm³

6 0
2 years ago
To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance.
kap26 [50]

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

In spectrophotometry, to plot the calibration curve, you need to prepare solutions with known concentrations and measure their absorbance.

We have a standard iron solution with a concentration of 0.2500g/L of pure iron (C₁). We pipet 25.00mL (V₁) of this standard iron solution into a 500mL (V₂) volumetric flask and dilute up to the mark with distilled water.

We can calculate the concentration of the diluted solution (C₂) using the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\\\C_2 = \frac{C_1 \times V_1}{V_2}  = \frac{0.2500 g/L \times 25.00 mL}{500 mL} = 0.0125 g/L

Then, if we wanted to prepare the blank, that is, the solution that contains the same matrix but not the analyte, and whose concentration in iron is 0.00 mg/L, we wouldn't pipet any of the diluted solution.

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

Learn  more: brainly.com/question/24195565

8 0
2 years ago
Can someone please answer this for me I need help I’ll give brainliest :((((
Ahat [919]
B) As water temp increases solubility increases
6 0
3 years ago
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