Please help<br><br>why does 45° produce a max. range?

Please help me with this question ASAP.

victus00 [196]

Answer:

i. 6.923 V

ii. The e.m.f. = 22.5 V

Explanation:

i. The given parameters are;

Length of potentiometer = 1 m

The resistance of the potentiometer = 10 Ω

The e. m. f. of the attached cell = 9 V

The current, I flowing in the circuit = e. m. f/(Total resistance)

The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A

The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire

The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V

ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;

$\dfrac{E}{R_{balance}} = \dfrac{V}{R_{cell}}$

Where:

E = e.m.f. of the balance point cell

$R_{balance}$ = Resistance of 75 cm of potentiometer wire = 0.75×10 = 7.5 Ω

$R_{cell}$ = Resistance of the cell in the circuit = 3 Ω

V = e.m.f. attached cell = 9 V

$\dfrac{E}{7.5} = \dfrac{9}{3}$

E = 7.5*3 = 22.5 V

The e.m.f. = 22.5 V

7 0

4 years ago

describe how light reflecting from a mirror can produce an image. In particular, explain how mirrors can produce images that are

VikaD [51]

Answer:

A larger image is produced when $d_i$ > $d_o$

A smaller image is produced when $d_i$ < $d_o$

An upright image is produced when m is positive

An upright image is produced when m is negative

Explanation:

The mirror equation is given as follows;

$\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}$

$m =-\dfrac{d_i}{d_o} = \dfrac{h_i}{h_o}$

For concave mirrors, f = focal length

$d_i$ = Image distance from the mirror (-ve $d_i$ = Image is behind the mirror +ve $d_i$ = Image is in front of the mirror)

$d_o$ = Object distance from the mirror (-ve $d_o$ = Object is behind the mirror +ve $d_o$ = Object is in front of the mirror)

m = Magnification (-ve m = Inverted image +ve m = upright image)

$h_i$ = Image height

$h_o$ = Object height

f = Focal length of the mirror

To produce a larger image $d_i$ > $d_o$

To produce a smaller image $d_i$ < $d_o$

To produce an upright image, m should be positive hence, $d_i$ will be negative or the image will appear behind the mirror

To produce an inverted image, m should be negative hence, $d_i$ will be positive or the image will form in front of the mirror.

5 0

3 years ago

The specific heat of gold is 0.031 calories/gram°C and the specific heat of silver is 0.057 calories/gram°C. If equal amounts of

Nady [450]

The gold will heat up almost twice as fast. The specific heat of a metal tells us just how much calories is needed to change the temperature of a metal by 1 degree celsius. Given this, the smaller the specific heat of a metal, the faster it will heat up.

3 0

3 years ago

What structure holds donor sperm in earthworms

lidiya [134]

Answer:

Explanation: As the earthworm passes through the slime tube, the tube will pass over the female pore picking up eggs. The tube will continue to move down the earthworm and pass over the male pore called the spermatheca which has the stored sperm called the spermatozoa.

4 0

3 years ago

Bales of hay of 40 lbf move up a conveyor set at 30° angle to the ground. If the hay bales are moving at 1.5 ft/sec, determine t

jekas [21]

Answer:

The power required to move each bale is 30 lbf.ft/sec.

Explanation:

F= 40lbf * sin (30º)

F=20lbf

P= F*v

P=20 lbf * 1.5 ft/sec

P= 30 lbf.ft/sec

5 0

4 years ago

Please helpwhy does 45° produce a max. range?​

Please helpwhy does 45° produce a max. range?