Fe=K Q1/Q2/d2
Q1 is the first charge
Q2 is the second charge
d is the distance
K= 9x10^9 NM^2/C2
Now let’s plug the numbers
Fe=9x10^9NM^2/C2 (2x10^-4C)(8x10^-4C) / (0.3m^2) you notice we took away the negative charges when we plugged the charges
Ok now we notice that we have C2 which is C to the power 2 we can write it as C^2 and we have two CSU’s beside each one of the charges we can get rid of them all by curtailment
And we can curtailment the M^2and the other M^2
Now we left with only 9x10^9N (2x10^-4)(8x10^-4)/ 0.3
Let’s multiply the (9)(2)(8)=144
And add the exponents (9)+(-4)+(-4)=1
So now we got 144x10N divide by the distance which is 0.3
144x10N / 0.3 = 4800N
Hope it helps u understand :)
Answer: The final volume of the gas is 1.12 L
Explanation:
W = work done on or by the system
w = work done by the system = 
P = pressure = 783 torr = 1.03 atm (1atm=760 torr)
w= 110.8 J = 1.094 J (1Latm=101.3J)
= initial volume = 57.8 ml = 0.0578L (1L=1000ml)
= final volume = ?
The final volume of the gas is 1.12 L
Your answer would be 4.0 hz.
Answer:
C
Explanation:
Foot-in-the-door technique is a compliance tactic that aims at getting a person to agree to a large request by having them agree to a modest request first
