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mihalych1998 [28]
2 years ago
12

Please helpwhy does 45° produce a max. range?​

Physics
1 answer:
lesya692 [45]2 years ago
8 0

Answer:

i do not know

Explanation:

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Galileo held that measurements of time were _____ and that measurements of distance were ______. absolute; relative
DanielleElmas [232]

Answer:

option A

Explanation:

the correct answer is option A

The given blanks in the question will be filled with Absolute and relative receptively.

time is absolute means the numerical representation of time example 12:00 pm is absolute time.

Measurement of distance is relative. A relative distance is one which is represented with the reference of some other place, it is not an exact value.

6 0
3 years ago
What is the momentum of a vehicle that has a mass of 800 kg and is moving at a velocity of 5 m/s
yarga [219]

Answer:

4000 kg.m/s

Explanation:

p=mv

m=800 kg

v=5 m/s

p=(800)(5)= 4000 kg.m/s

3 0
3 years ago
Which example best illustrates kinetic energy?
mihalych1998 [28]

Answer:

A.

Explanation:

In all actuality. The car may not be fully moving but since it's on a hill and the earth moves it makes the most sense. Also since the car is at a slope by the law of motion what goes up must come down so the car is in fact moving.

8 0
3 years ago
Read 2 more answers
So lost on this one number 1 ?
kirza4 [7]

Read each statement, one at a time, and form the picture in your mind.

<em>Statement #1</em> should make you feel all warm and fuzzy inside.

Statements #2, #3, and #4 should make your red flag wave on the inside, and should make you giggle on the outside when you realize how absurd each of those is.

5 0
2 years ago
A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
Masja [62]

Explanation:

We have,

Height of object is 5 cm

Object distance from a convex lens is 18 cm

Focal length of convex lens is 10 cm

i.e. h = 5 cm

u = -18 cm

f = +10 cm

Let v is distance of the image from the lens. Using lens formula :

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-18)}\\\\v=22.5\ cm

The magnification of lens is :

m=\dfrac{v}{u}=\dfrac{h'}{h}, h' is height of the image

\dfrac{v}{u}=\dfrac{h'}{h}\\\\h'=\dfrac{vh}{u}\\\\h'=\dfrac{22.5\times 4}{(-18)}\\\\h'=-5\ cm

h' = -5.00 cm (in three significant figures)

6 0
3 years ago
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