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3 years ago

A bus traveling at 24 m/s slows down to 12 m/s in 5.0 seconds. What is the acceleration?

Physics

1 answer:

Contact [7]3 years ago

8 0

Answer:

a = -2.4 m/s²

Explanation:

Given,

The initial speed of the bus, u = 24 m/s

The final speed of bus, v = 12 m/s

Time taken to reach final speed is, t = 5.0 s

The acceleration of the body is given by the change in velocity by time

a = (v - u) / t

= (12 - 24) / 5

= -2.4 m/s²

The negative sign in the acceleration indicates that the bus is decelerating.

Therefore, the acceleration of the bus is, a = -2.4 m/s²

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A shuttle bus slows down with an average acceleration of -2.4 m/s2. How long does it

olganol [36]

Answer:

$\boxed {\boxed {\sf 3.75 \ seconds }}$

Explanation:

Average acceleration is found by dividing the change in acceleration by the time.

$a=\frac{ v_f-v_i}{t}$

The shuttle bus has an acceleration of -2.4 meters per square second. It slows from 9.0 meters per second to rest, or 0 meters per second. Therefore:

$a= -2.4 \ m/s^2 \\v_f= 0 \ m/s \\v_i= 9 \ m/s$

Substitute the values into the formula.

$-2.4 \ m/s^2=\frac{0 \ m/s - 9 \ m/s}{t }$

Solve the numerator.

$-2.4 \ m/s^2 = \frac{-9 \ m/s}{t}$

We want to solve for t, the time. We have to isolate the variable. Let's cross multiply.

$\frac{-2.4 \ m/s^2}{1} = \frac{-9 \ m/s}{t}$

$-9 \ m/s *1= -2.4 \ m/s^2 *t$

$-9 \ m/s=-2.4 m/s^2*t$

t is being multiplied by -2.4. The inverse of multiplication is division, so divide both sides by -2.4

$\frac{-9 \ m/s }{-2.4 \ m/s^2} =\frac{ -2.4 \ m/s^2*t}{-2.4 \ m/s^2}$

$\frac{-9 \ m/s }{-2.4 \ m/s^2} =t$

$3.75 \ s=t$

It takes <u>3.75 seconds.</u>

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Read 2 more answers

1) A crane uses an average force of 5,200 N to lift a girder 25 m. How much work does the crane do on the girder?

Andrej [43]

Answer:

1) 130, 000 J

2) 1 J

Explanation:

Work done is product of force in Newtons and distance in meters

W=Fd

Given an average force of 5,200 N and distance of 25 m then we evaluate that

Work done=5200*25=130, 000 Nm or Joules

Similarly, for the second question, given force of 1N and distace of 1 m then the work done will be

W=1*1=1 J

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