Answer:
Living means something which biologically active, and can function naturally.
Non loving is something which cannot function naturally and biologically.
Dead is something that was living for a certain period, but now it doesn't.
The correct answer to the question is : D) Impulse
EXPLANATION:
Before going to answer this question, first we have to understand impulse.
Impulse of a body is defined as change in momentum or the product of force with time.
Mathematically impulse = F × t = m ( v - u ).
Here, v is the final velocity
u is the initial velocity
F is the force acting on the body for time t.
Hence, the perfect answer of this question is impulse m i.e the force multiplied with time is known as impulse.
To solve this exercise it is necessary to use the concepts related to Difference in Phase.
The Difference in phase is given by

Where
Horizontal distance between two points
Wavelength
From our values we have,


The horizontal distance between this two points would be given for

Therefore using the equation we have




Therefore the correct answer is C.