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erastovalidia [21]
3 years ago
9

Where does the energy of a hurricane come from? (1 point)

Chemistry
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

strong winds come from the energy of a hurricane

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Please help!! my grades dying <br> 15 points
AysviL [449]

Answers-in-bold:

There are two common temperature scales. On the Fahrenheit scale, water freezes at 32 degrees. The Celsius scale divides the interval between the freezing and boiling points of water into 100 degrees.

4 0
3 years ago
2h3po4 + 3mg(oh)2 → mg3(po4)2 + 6h2o phosphoric acid, h3po4, is neutralized by magnesium hydroxide, mg(oh)2, according to the eq
Rina8888 [55]
The balanced equation for the neutralisation reaction is as follows
2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O
stoichiometry of H₃PO₄ to H₂O is 2:6
number of H₃PO₄ moles reacted - 0.24 mol
if 2 mol of H₃PO₄ form 6 mol of H₂O
then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O
therefore 0.72 mol of H₂O are formed 
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4 years ago
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5 0
2 years ago
Cell notation will list each half-reaction:
likoan [24]

Answer:

on each side of the salt bridge, which is represented by a double vertical line

Explanation:

While writing a cell notation, the general convention is; anode || cathode. The anode and the cathode are separated by a double line. The anode is written on the lefthand side while the cathode is written on the righthand side.

The cell notation is a shorthand representation of a cell, hence any electrochemical cell can easily be produced based on its cell diagram.

6 0
3 years ago
Farmers who raise cotton once used arsenic acid, H₃AsO₄, as a defoliant at harvest time. Arsenic acid is a polyprotic acid with
Stels [109]

Explanation:

The reaction equation will be as follows.

      H_{3}AsO_{4} \rightleftharpoons H_{2}AsO^{-}_{4} + H^{+}

Hence, the expression for K_{a} is as follows.

            K_{a} = \frac{[H_{2}SO^{-}_{4}][H^{+}]}{[H_{3}AsO_{4}]}

Let us assume that the concentration of both [H_{2}AsO^{-}_{4}] and [H^{+}] is x.

           2.5 \times 10^{-4} = \frac{x \times x}{0.5}

                          x = 0.01118034

This means that the concentration of [H^{+}] is 0.01118034.

Since, we know that the relation between pH and concentration of hydrogen ions is as follows.

              pH = -log [H^{+}]

                    = -log (0.01118034)

                    = 1.958

Thus, we can conclude that the pH of a 0.500 M solution of arsenic acid is 1.958.

6 0
4 years ago
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