No, unless the slime or paper is wet.
<span>1.304 x 10^7! Hope this helped.</span>
Answer:
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Explanation:
The concentration of the solution is given by :
![[C]=\frac{\text{Moles of compound}}{\text{Volume of solution in Liters}}](https://tex.z-dn.net/?f=%5BC%5D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20compound%7D%7D%7B%5Ctext%7BVolume%20of%20solution%20in%20Liters%7D%7D)
We have:
Concentration of copper (II) nitrate solution = ![[Cu(NO_3)_2]=2.41 M](https://tex.z-dn.net/?f=%5BCu%28NO_3%29_2%5D%3D2.41%20M)
The volume of solution = 4.12 mL
1 mL= 0.001 L

Moles of copper (II) nitrate in solution = n

Moles of copper (II) nitrate in solution = 0.0099292 mol
1 Mole of copper(II) nitrate has 1 mole of copper then 0.0099292 moles of copper(II) nitrate will have :

Mass of 0.0099292 moles of copper:

This mass of copper present in the solution is the theoretical mass of copper present in the given copper(II) nitrate solution.
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Answer:
Atoms are composed of electrically charged particles and moving electric charges possess an associated magnetic field.
Explanation:
An atom is made up of electrons arranged in shells. Electrons are negatively charged. These charged particles produce an electric field which can interact with an external electric field to give information about atomic structure.
Similarly, a moving electron produces an associated magnetic field which can couple with an external magnetic field to give information about atomic structure.
Answer:
4200ml
Explanation:
Converting 3.1kg to g
3.1*1000= 3100g
Since density = mass/volume, then
volume = mass/ density
Therefore volume = 3100/0.74
= 4189.2ml
converting it to two significant figures
= 4200ml