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andrey2020 [161]
2 years ago
14

A 20 N force pulls to the right and friction pulls 5 N. If the mass is 5 kg, find acceleration.​

Physics
1 answer:
Slav-nsk [51]2 years ago
7 0

Answer:

Explanation:

Force - frictional Force = m * a

20N - 5N = 5 * a

15N = 5*a

15N / 5 = a

a = 3 m/s^2

You should note a couple of things.

1. The frictional Force always opposes the direction of motion. In this case it is minus and the 20 N is plus. It makes the acceleration less. If the friction force was not there then 20 N = m * a

20N = 5 kg * a

a = 20/5

a = 4 m/s^2.

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Answer:

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S = Vt + S0

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From this you can calculate t, if that's what you want.

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Answer:

speed of plane in still air = 1060 km/h

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Explanation:

Let teh speed of plane in still air is vp and the speed of air is va.

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So,

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5 0
3 years ago
A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?
Yanka [14]

Answer:

\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 380.2 \times  {11}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 190.1 \times 121

\sf \implies KE = 190.1 \times 121

\sf \implies KE = 23002.1 \: J

\therefore

Kinetic energy of the polar bear (KE) = 23002.1 J

5 0
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