Can you write out the question please? :) Sorry, i don't see it on the paper
Answer:
0.325 N
Explanation:
From the question,
T = 4π²rm/t²............................ Equation 1
Where T = Tension, r = radius or length of the string, m = mass of the string, t = time.
Given: r = 2.4 m, m = 15 g = 0.015 kg, t = 2.09 s.
Constant: π = 3.14
Substitute these values into equation 1
T = 4(3.14²)(2.4)(0.015)/2.09²
T = 1.4198/4.3681
T = 0.325 N
Answer:
1476 J
Explanation:
From the question,
Net Work done = Net force× distance moved by net force.
W' = (F-F')×d................... Equation 1
Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.
Given: F = 150 N, F' = 37 N, d = 12 m
Substitute these values into equation 1
W' = (150-37)×12
W' = 123×12
W' = 1476 J.
hence the Net Work done by the object is 1476 J
Answer:
20 m/s
Explanation:
Height (s)= 20m
acceleration (a) = 10 m/s^2
v=?
we know,
V^2= U^2 + 2as. (U is initial velocity)
or,. V^2 = 0 + 2 × 10 × 20
or, V^2 = 400
or,. V = 20 m/s
