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anzhelika [568]
3 years ago
11

Which is true of a step-down transformer but not a step-up transformer? The core is made of copper and the coils are made of iro

n. The core is made of iron and the coils are made of copper. The primary winding has fewer coils than the secondary winding. The primary winding has more coils than the secondary winding.
Physics
2 answers:
Lina20 [59]3 years ago
6 0

Answer:

D

Explanation:

Agata [3.3K]3 years ago
3 0

The primary winding has more coils than the secondary winding

Explanation:

A transformer is a device consisting of two coils (called primary and secondary coil) wrapped around a soft iron core. As the primary coil is connected to alternate voltage, a variable magnetic field inside the iron core is produced; the lines of this field cut also the secondary coil, and due to the phenomenon of electromagnetic induction, an e.m.f is produced in the secondary coil (so, an alternate voltage).

The voltages in the two coils are related by the transformer equation:

\frac{V_1}{V_2}=\frac{N_1}{N_2} (1)

where

V_1 is the voltage in the primary coil

V_2 is the voltage in the secondary coil

N_1 is the number of turns in the primary coil

N_2 is the number of turns in the secondary coil

In a step-down transformer, the voltage in the secondary coil is lower than the voltage in the primary coil (they are used to decrease the voltage in input), therefore:

\frac{V_1}{V_2}>1

which means, according to eq.(1),

\frac{N_1}{N_2}>1

So

N_2

Therefore the correct answer is

The primary winding has more coils than the secondary winding.

Learn more about voltage:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

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A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5
Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

S = ut + \frac {1}{2}at^{2}

Substituting into the equation, we have;

S =20*5 + \frac{1}{2}*(-4)*5^{2}

S =100 + (-2)*25

S =100 - 50

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.

<em>Substituting into the equation, we have;</em>

V^{2} = 20^{2} + 2(-4)*50

V^{2} = 400 - 400

V^{2} = 0

V = 0m/s

<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>

5 0
3 years ago
A 15.0-kilogram mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the
Mars2501 [29]
The answer is 570 J. The kinetic energy has the formula of 1/2mV². The total work in this process W= 1/2m(V2²-V1²) = 1/2 * 15.0 * (11.5²-7.50²) = 570 J.
7 0
4 years ago
Which of the following statements best characterizes the surface of the planet Mars?The surface of Mars is continuously resurfac
butalik [34]

All the big volcanoes are in the northern hemisphere of Mars, and most of the craters are in the southern hemisphere is of the following statements that best characterizes the surface of the planet Mars.


Hope this helps,

Davinia.

4 0
4 years ago
Gravitational potential energy is due to....
mote1985 [20]

Answer:

A

Explanation:

I only think its A because of the gravity part...sorry im not good at explaining

5 0
3 years ago
Suppose 8.41 moles of a monatomic ideal gas expand adiabatically, and its temperature decreases from 395 to 279 K. Determine (a)
sergeinik [125]

Answer:

a) W=12166.20876 J

b) U= -12166.20876 J

Explanation:

No. of moles, n = 8.41

Change of temperature, ΔT = T1 - T2

                                         = 395 - 279

                                         = 116 K

For monatomic gas, γ = 5/3

γ -1 = 2 /3

Solution:

(a)

Work done,W= \frac{nR}{\gamma-1}(T_1-T_2)

plugging values we get

W= \frac{8.314\times8.41}{2/3}(116)

Ans:   12166.20876 J

Work done, W = + 12166.20876 J

(b)

From first law of thermodynamics, dQ = U + W

but, dQ = 0 ( adiabatic process)

Hence, U = - W

                 = - 12166.20876 J

Ans:

Change in internal energy, U = - 12166.20876 J

8 0
3 years ago
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