Answer:
None of these
Explanation:
The mass percent is 35.4% (3 s.f.)
14/4+35.5 = 14/39.5 x 100 = 35.4 (3 s.f.)
2 moles N
2 moles H
3 moles O
<h3>Further explanation</h3>
Given
The compound is probably NH₂NO₃
Required
The number of moles
Solution
there are 2 N in NH₂NO₃, so moles N = 2moles
there are 2 H in NH₂NO₃, so moles H = 2moles
there are 3 O in NH₂NO₃, so moles O = 3 moles
Answer:
Sulfur (Option-C) <span>exhibits chemical behavior similar to that of oxygen.
Explanation:
Sulfur has same chemical properties as that of Oxygen because both of them belongs to same group in the periodic table. Also, the similarity of chemical behaviour among the group members is due to same number of electrons in their valence shells.
For examole, the electronic configuration of Oxygen is,
1s</span>², 2s², 2p⁴
There are six valence electrons in the valence shell (i.e. 2) of Oxygen.
Now for Sulfur,
1s², 2s², 2p⁶, 3s², 3p⁴
There are six valence electrons in the valence shell (i.e. 3) of Sulfur.
Therefore, both elements tends to gain 2 electrons in a reaction and form O⁻² and S⁻² respectively.
Answer:
The volume of ammonia produced by 4.2 L of hydrogen and excess nitrogen is 2.8 L.
Explanation:
Given data:
Volume of H₂ = 4.2 L
Volume of NH₃ produced = ?
Solution:
First of all we will write the balance chemical equation:
N₂ + 3H₂ → 2NH₃
Hydrogen is limiting reactant and volume ratio is,
H₂ : NH₃
3 : 2
4.2 : 2/3 × 4.2 = 2.8 L
The volume of ammonia produced by 4.2 L of hydrogen and excess nitrogen is 2.8 L.